UVA294 - Divisors
来源:互联网 发布:氨基酸数据库 编辑:程序博客网 时间:2024/06/14 16:47
用j*j==i 来降低复杂度
#include<stdio.h>int main(){ int T; scanf("%d",&T); while(T--){ int a, b; scanf("%d %d",&a,&b); int best=0,num=0,i,j; for(i =a; i<=b; i++){ int num_i=0; for(j = 1;j*j<=i ;j++){ if(i%j==0) num_i+=2; } if((j-1)*(j-1)==i) num_i--; if(num_i>num) best=i,num=num_i; } printf("Between %d and %d, %d has a maximum of %d divisors.\n",a,b,best,num); } return 0;}
0 0
- UVa294 - Divisors
- UVa294 Divisors
- UVA294 - Divisors
- uva294 Divisors
- uva294
- Divisors
- Divisors
- Divisors
- 习题10-9 约数 UVa294
- JOJ1716:Divisors
- pku2992 Divisors
- POJ2992 Divisors
- poj_2992 Divisors
- Common Divisors
- hihocodxer1187 Divisors
- Counting Divisors
- Counting Divisors
- HDU6069Counting Divisors
- PL/SQL 动态 SQL
- HDU 2243 考研路茫茫——单词情结(自动机DP+矩阵)
- 括号匹配
- Java程序单元测试工具对比——Parasoft Jtest与Junit
- GCC环境变量设置
- UVA294 - Divisors
- (Android入门)Android四大组件
- Performance and Optimization For Mecanim[Unity]
- 3.7
- win7+ubuntu14.04双系统,重装win7后,修复grub方法
- mysql数据库备份
- [统计学习方法]决策树
- 关于typedef的用法总结
- PAT A1007Maximum Subsequence Sum(贪心算法)