Problem C: Chicken and rabbits
来源:互联网 发布:vip软件 编辑:程序博客网 时间:2024/05/16 05:25
Problem C: Chicken and rabbits
Time Limit: 1 Sec Memory Limit: 32 MBSubmit: 75 Solved: 21
[Submit][Status][Web Board]
Description
Chicken and rabbits are in a same cage. As we all know, chicken has two legs but rabbit has four. Now
we know the number of legs in the cage is A, please tell me how many animals may in the cage at least
and at most.
Input
The first line of the input contains the number of test cases in the file. Each test case that follows
consists of one lines. each case contains only one integer numbers A specifying the total legs in the
cage .
Output
For each test case, print a line contains the answer
Sample Input
2320
Sample Output
0 05 10
HINT
这一题,很简单,但是得看到一个错误!那就是数据2,当时我没看到,错了!
不过现在这个代码友好多了!
#include <stdio.h>int main(){int times,n,max,min;scanf("%d",×);while (times--){scanf("%d",&n);if (n%2!=0){printf("0 0\n");}else{max=n/2;if (n%4==0){min=n/4;}else{min=n/4+1;}printf("%d %d\n",min,max);}}}
0 0
- Problem C: Chicken and rabbits
- chicken-and-egg problem的一些想法
- hdu3639 Hawk-and-Chicken
- hdu3639Hawk-and-Chicken
- hdu3639Hawk-and-Chicken
- hdu3639 Hawk-and-Chicken
- HDU3639 Hawk-and-Chicken
- Hawk-and-Chicken HDU
- Hawk-and-Chicken
- Rabbits and Recurrence Relations
- hdoj 3639 Hawk-and-Chicken
- hdu3639 Hawk-and-Chicken (Tarjan)
- HDU 3639 Hawk-and-Chicken
- HDOJ 3639 Hawk-and-Chicken
- HDOJ 3639 Hawk-and-Chicken
- HDU 3639 Hawk-and-Chicken 支持传递
- [tarjan] hdu 3639 Hawk-and-Chicken
- 连通图之HDU3639 Hawk-and-Chicken
- JDBC 链接案例—— 纯代码,无连接池
- C语言中的static变量和static函数
- 第24天【健身】
- 【SSH进阶之路】一步步重构容器实现Spring框架——彻底封装,实现简单灵活的Spring框架(十一)
- android 获取相册列表的实现及源码下载(二)
- Problem C: Chicken and rabbits
- 架构说明
- extern "C"的用法解析
- nfs配置及常见错误
- Java--正则表达式及应用
- 线程池简介
- nyoj-1143-数字游戏
- Swift 读取,处理Json数据
- SAP的账期分析和操作