厄密多项式 --递归

#include<stdio.h>int hermite(int n, int x){if ( n <= 0 )             return 1;else if ( n  = 1 )     return 2*x;else              return 2*x*hermite(n-1,x) - 2*(n-1)*hermite(n-2,x);}main(){int n,x,f;printf("厄密多项式：\n");printf("请分别输入n和x：");scanf("%d%d",&n,&x);f = hermite(n,x);printf("%d",f);}