用递归函数实现厄密多项式

#include<stdio.h>int hermite(int n, int x){if(n <= 0)return 1;if(n == 1)return 2*x;if(n >= 2)return 2*x*hermite(n-1,x) - 2*(n-1)*hermite(n-2,x);return 0;}int main(){int n,x;int a;scanf("%d%d",&n,&x);a = hermite(n,x);printf("a = %d\n",a);return 0;}