【C++】保存和读取有规律格式的文件路径

来源：互联网发布：python chain list 编辑：程序博客网时间：2024/05/16 18:12

我需要对文件样本进行训练，有10*50=500个样本，所以训练之前写个存入和读取程序，方便操作。文件格式规律如下：

charSamples\0\0 (1).png

charSamples\0\0 (2).png

charSamples\9\9 (50).png

#include <vector>#include <iostream>#include <fstream>#include "opencv2/highgui/highgui.hpp"  #include "opencv2/imgproc/imgproc.hpp"  #include "opencv2/core/core.hpp"#include <opencv\ml.h>#include <string>using namespace cv;using namespace std;vector<string> readfiles(string FilePath){char buffer[256];vector<string> bufstr;fstream out;out.open(FilePath,ios::in);cout<<"com.txt"<<" 的内容如下:"<<endl;while(!out.eof()){   out.getline(buffer,256,'\n');   bufstr.push_back(buffer);   cout<<buffer<<endl;}out.close();return bufstr;}int write2txt(string savename){char buf[50];vector<string> savevec;ofstream save(savename,ios::out);int counts = 0;for(int a =0;a<10;a++){for(int j =1;j<51;j++){sprintf(buf,"charSamples\\%d\\%d (%d).png\n",a,a,j);save<<buf;savevec.push_back(buf);counts+=1;}}save.close();return counts;}int main(){string savename = "4-11.txt";int n = write2txt(savename);readfiles(savename);cout<<"successful write files num:"<<n<<endl;waitKey();return 0;}

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输出保存的TXT文件：

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