LeetCode - Candy

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https://leetcode.com/problems/candy/

There are N children standing in a line. Each child is assigned a rating value.

You are giving candies to these children subjected to the following requirements:

  • Each child must have at least one candy.
  • Children with a higher rating get more candies than their neighbors.

What is the minimum candies you must give?

这道题的解法是:

1.从左往右扫描,如果当前数比前一个数大,那么当前位置的糖果是前一位置的糖果加1,否则当前位置糖果为1.

2.从右往左扫描,如果当前数比后一个数大,那么当前位置的糖果是后一位置的糖果加1和自己本身有的糖果数的最大值,否则保持自己的糖果数不变。

3.扫描candy数组,求和。

public class Solution {    public int candy(int[] ratings) {        int[] candy = new int[ratings.length];        candy[0] = 1;        for(int i=1; i<ratings.length; i++){            if(ratings[i]>ratings[i-1]) candy[i]=candy[i-1]+1;            else candy[i] = 1;        }        for(int i=ratings.length-2; i>=0; i--){            if(ratings[i]>ratings[i+1]) candy[i] = Math.max(candy[i], candy[i+1]+1);        }        int total = 0;        for(int i=0; i<candy.length; i++){            total += candy[i];        }        return total;    }}


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