splice函数

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http://www.cplusplus.com/reference/list/list/splice/

entire list (1)

void splice (iterator position, list& x);

single element (2)

void splice (iterator position, list& x, iterator i);

element range (3)

void splice (iterator position, list& x, iterator first, iterator last);

The first version (1) transfers all the elements of x into the container.
The second version (2) transfers only the element pointed by i from x into the container.
The third version (3) transfers the range [first,last) from x into the container.

// splicing lists#include <iostream>#include <list>int main (){  std::list<int> mylist1, mylist2;  std::list<int>::iterator it;  // set some initial values:  for (int i=1; i<=4; ++i)     mylist1.push_back(i);      // mylist1: 1 2 3 4  for (int i=1; i<=3; ++i)     mylist2.push_back(i*10);   // mylist2: 10 20 30  it = mylist1.begin();  ++it;                         // points to 2  mylist1.splice (it, mylist2); // mylist1: 1 10 20 30 2 3 4                                // mylist2 (empty)                                // "it" still points to 2 (the 5th element)                                            mylist2.splice (mylist2.begin(),mylist1, it);                                // mylist1: 1 10 20 30 3 4                                // mylist2: 2                                // "it" is now invalid.  it = mylist1.begin();  std::advance(it,3);           // "it" points now to 30  mylist1.splice ( mylist1.begin(), mylist1, it, mylist1.end());                                // mylist1: 30 3 4 1 10 20  std::cout << "mylist1 contains:";  for (it=mylist1.begin(); it!=mylist1.end(); ++it)    std::cout << ' ' << *it;  std::cout << '\n';  std::cout << "mylist2 contains:";  for (it=mylist2.begin(); it!=mylist2.end(); ++it)    std::cout << ' ' << *it;  std::cout << '\n';  return 0;}

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