DFS Letter Combinations of a Phone Number
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思想：
DFS
class Solution {public: const vector<string> dict={"","","abc","def","ghi","jkl","mno","pqrs","tuv","wxyz"}; void dfs(string digits, int depth, string path, vector<string> &res) { if(depth == digits.size()) { res.push_back(path); return; } for(auto c: dict[digits[depth] - '0']) { dfs(digits, depth+1, path+c, res); } } vector<string> letterCombinations(string digits) { vector<string> res; if(digits.size() == 0) return res; dfs(digits, 0, "", res); return res; }}; 0 0
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