05-树6. Path in a Heap

Insert a sequence of given numbers into an initially empty min-heap H. Then for any given index i, you are supposed to print the path from H[i] to the root.

Input Specification:

Each input file contains one test case. For each case, the first line gives two positive integers N and M (<=1000) which are the size of the input sequence, and the number of indices to be checked, respectively. Given in the next line are the N integers in [-10000, 10000] which are supposed to be inserted into an initially empty min-heap. Finally in the last line, M indices are given.

Output Specification:

For each index i in the input, print in one line the numbers visited along the path from H[i] to the root of the heap. The numbers are separated by a space, and there must be no extra space at the end of the line.
Sample Input:5 3
46 23 26 24 10
5 4 3

Sample Output:24 23 10
46 23 10
26 10

这题属于二叉堆的练手题，开始以为二叉堆很难。 。结果发现还是比AVL和CBT容易一些。coding不到半小时就AC了。 。好久没有这么痛快了。

#include<stdio.h>int IsFull(int n,int i);void Insert(int* p,int k,int i);int main(){    int m,n,i,k;    scanf("%d%d",&m,&n);    int heap[m+1];    heap[0] = -20000;//  构建heap     for(i = 1;i<=m;i++){        scanf("%d",&k);        if(1 == i)            heap[i] = k;        else{            if(IsFull(m,i-1))                break;            else                Insert(heap,k,i);               }    }//  读取，输出    for(i = 0;i<n;i++){        scanf("%d",&k);        for(int j = k;j;j/=2){            if(j == k)                printf("%d",heap[j]);            else                printf(" %d",heap[j]);        }        if(i!=n-1)            printf("\n");    }     return 0;} void Insert(int* p,int k,int i){    for(;p[i/2]>k;i/=2)        p[i] = p[i/2];    p[i] = k;}int IsFull(int n,int i){    if(n == i)        return 1;    return 0;}