山东省第二届ACM大学生程序设计竞赛——Mathman Bank

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题目链接:http://acm.sdut.edu.cn/sdutoj/problem.php?action=showproblem&problemid=2167
Mathman Bank

简单模拟即可！！！
#include<iostream>#include<cstdio>#include<string>#include<algorithm>using namespace std;struct node{    string name;    string pass;    int sum;}no[1010];int Find(string name,int k){    for(int i=0;i<k;i++)        if(no[i].name==name)            return i;    return -1;}int main(){    int n;    char op;    string name,pass,name2,pass2;    int sum;    int k;    while(cin>>n)    {        k=0;        while(n--)        {            cin>>op;            if(op=='O')            {                cin>>name>>pass>>sum;                if(Find(name,k)!=-1)                    printf("Account exists.\n");                else                {                    no[k].name=name;                    no[k].pass=pass;                    no[k].sum=sum;                    k++;                    printf("Successfully opened an account.\n");                }            }            else if(op=='D')            {                cin>>name>>sum;                if(Find(name,k)!=-1)                {                    no[Find(name,k)].sum+=sum;                        printf("Successfully deposited money.\n");                }                else                    printf("Account does not exist.\n");            }            else if(op=='W')            {                cin>>name>>pass>>sum;                if(Find(name,k)!=-1)                {                    if(no[Find(name,k)].pass==pass)                        if(no[Find(name,k)].sum>=sum)                            {                                no[Find(name,k)].sum-=sum;                                printf("Successfully withdrew money.\n");                            }                        else                            printf("Money not enough.\n");                    else                        printf("Wrong password.\n");                }                else                    printf("Account does not exist.\n");            }            else if(op=='T')            {                cin>>name>>pass>>name2>>sum;                if(Find(name,k)!=-1&&Find(name2,k)!=-1) //这里应该先判断两个账号是否存在，再判断第一个账号的密码是否正确                {                    if(no[Find(name,k)].pass==pass)                        if(no[Find(name,k)].sum>=sum)                            {                                no[Find(name,k)].sum-=sum;                                no[Find(name2,k)].sum+=sum;                                printf("Successfully transfered money.\n");                            }                        else                            printf("Money not enough.\n");                    else                        printf("Wrong password.\n");                }                else                    printf("Account does not exist.\n");            }            else if(op=='C')            {                cin>>name>>pass;                if(Find(name,k)!=-1)                {                    if(no[Find(name,k)].pass==pass)                        printf("%d\n",no[Find(name,k)].sum);                    else                        printf("Wrong password.\n");                }                else                    printf("Account does not exist.\n");            }            else            {                cin>>name>>pass>>pass2;                if(Find(name,k)!=-1)                {                    if(no[Find(name,k)].pass==pass)                    {                        no[Find(name,k)].pass=pass2;                        printf("Successfully changed password.\n");                    }                    else                        printf("Wrong password.\n");                }                else                    printf("Account does not exist.\n");            }        }    }    return 0;}
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