Pascal's Triangle II
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比一式简单,至少不用返回多维数组。
不过不知为何再翻回来的时候OJ的函数申明貌似跟AC的不一样了,但反正当时是AC了的。
如下:
struct IntArray { int* elements; int size;};struct IntArray* getRow(int rowIndex) { if (rowIndex < 0) return NULL; struct IntArray *result = (struct IntArray *)malloc(sizeof(struct IntArray)); result->elements = (int *)malloc(sizeof(int) * (rowIndex + 1)); result->elements[0] = 1; result->size = rowIndex + 1; if (rowIndex == 0) return result; int lastleft = 0, last = 0; for (int i = 1; i <= rowIndex; i++) { for (int j = 0; j <= i; j++) { if (j - 1 < 0) lastleft = 0; else lastleft = last; if (j == i) { result->elements[j] = 1; continue; } last = result->elements[j]; result->elements[j] = lastleft + last; } } return result;}
解答的更简单:
class Solution {public:vector<int> getRow(int rowIndex) {vector<int> array;for (int i = 0; i <= rowIndex; i++) {for (int j = i - 1; j > 0; j--){array[j] = array[j - 1] + array[j];}array.push_back(1);}return array;}};
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