HDU4706——Children's Day（简单模拟）

来源：互联网发布：歼十外销知乎编辑：程序博客网时间：2024/06/06 15:35

题目链接：

http://acm.hdu.edu.cn/showproblem.php?pid=4706

解题思路：

直接模拟就好了。。。

简单的水题。可是我模拟太烂了，没办法，比赛时，为了题数，只好暴力求解了...

AC代码：

#include<iostream>#include<cstdio>using namespace std;int main(){printf("a e\n");printf("bdf\n");printf("c g\n");printf("h  n\n");printf("i mo\n");printf("jl p\n");printf("k  q\n");printf("r   z\n");printf("s  ya\n");printf("t x b\n");printf("uw  c\n");printf("v   d\n");printf("e    o\n");printf("f   np\n");printf("g  m q\n");printf("h l  r\n");printf("ik   s\n");printf("j    t\n");printf("u     g\n");printf("v    fh\n");printf("w   e i\n");printf("x  d  j\n");printf("y c   k\n");printf("zb    l\n");printf("a     m\n");printf("n      b\n");printf("o     ac\n");printf("p    z d\n");printf("q   y  e\n");printf("r  x   f\n");printf("s w    g\n");printf("tv     h\n");printf("u      i\n");printf("j       z\n");printf("k      ya\n");printf("l     x b\n");printf("m    w  c\n");printf("n   v   d\n");printf("o  u    e\n");printf("p t     f\n");printf("qs      g\n");printf("r       h\n");printf("i        a\n");printf("j       zb\n");printf("k      y c\n");printf("l     x  d\n");printf("m    w   e\n");printf("n   v    f\n");printf("o  u     g\n");printf("p t      h\n");printf("qs       i\n");printf("r        j\n");return 0;}

另附两大牛AC代码：

#include <iostream>#include <cstdio>using namespace std;char str[100][100];int main(){    int cnt = 0;    for(int i = 3;i <= 10;i++){        for(int j = 0;j < i;j++){            for(int k = 0;k < i;k++)                str[j][k] = ' ';            str[j][i] = 0;        }        for(int j = 0;j < i;j++){            str[j][0] = 'a' + cnt;            cnt = (cnt+1)%26;        }        for(int j = i-2;j > 0;j--){            str[j][i-1-j] = 'a' + cnt;            cnt = (cnt+1)%26;        }        for(int j = 0;j < i;j++){            str[j][i-1] = 'a' + cnt;            cnt = (cnt+1)%26;        }        for(int j = 0;j < i;j++)            printf("%s\n",str[j]);    }    return 0;}

#include <stdio.h>const int N = 26;int solve(int n, int c){    int dist = 2 * (n - 1);    for (int i = 0; i < n; i++){        for (int j = 0; j < n; j++){            if (j == 0)                printf("%c", 'a' + (c + i) % N);            else if(j == n - 1)                printf("%c", 'a' + (c + i + dist) % N);            else if(i + j == n - 1)                printf("%c", 'a' + (i + c + (n - i - 1) * 2) % N);            else                printf(" ");        }        printf("\n");    }}int main(){    int t = 0;    for (int i = 3; i <= 10; i++){        solve(i, t);        t += i * 3 - 2;    }    return 0;}

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