杭电ACM1001Sum Problem(1~n的和)

Sum Problem

Time Limit: 1000/500 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 334319    Accepted Submission(s): 84056

Problem Description

Hey, welcome to HDOJ(Hangzhou Dianzi University Online Judge).

In this problem, your task is to calculate SUM(n) = 1 + 2 + 3 + ... + n.

 

Input

The input will consist of a series of integers n, one integer per line.

 

Output

For each case, output SUM(n) in one line, followed by a blank line. You may assume the result will be in the range of 32-bit signed integer.

 

Sample Input

1100

 

Sample Output

15050

注：此题为：杭电ACM1001Sum Problem(1~n的和)

说明：累加，注意输出格式

已AC源代码：

#include<stdio.h>int main(){int n;while(scanf("%d",&n)!=EOF){int i,sum=0;for(i=1;i<=n;i++){sum+=i;}printf("%d\n",sum);}return 0;}