第9周项目3-分数类中的运算符重载（续）

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问题描述：

在分数类中的运算符重载基础上

（1）定义分数的一目运算+和-，分别代表分数取正和求反，将“按位取反运算符”~重载为分数的求倒数运算。

（2）定义分数类中<<和>>运算符重载，实现分数的输入输出，改造原程序中对运算结果显示方式，使程序读起来更自然。

代码：

#include <iostream>#include <cmath>using namespace std;class CFraction{private:    int nume;    int deno;public:    CFraction(int n=0,int d=1):nume(n),deno(d){};    void display();    void simplify();    CFraction operator+(CFraction &c2);    CFraction operator-(CFraction &c2);    CFraction operator*(CFraction &c2);    CFraction operator/(CFraction &c2);    bool operator>(CFraction &c2);    bool operator<(CFraction &c2);    bool operator==(CFraction &c2);    bool operator!=(CFraction &c2);    bool operator>=(CFraction &c2);    bool operator<=(CFraction &c2);    CFraction operator+();    CFraction operator-();    CFraction operator~();    friend istream& operator>>(istream& in,CFraction &c);    friend ostream& operator<<(ostream& out,CFraction &c);};istream &operator>>(istream &in,CFraction &c){    char n;    cin>>c.nume>>n>>c.deno;    return in;}ostream& operator<<(ostream& out,CFraction &c){    cout<<c.nume<<"/"<<c.deno;    return out;}CFraction CFraction::operator~(){    return CFraction(deno,nume);}CFraction CFraction::operator+(){    return *this;}CFraction CFraction::operator-(){    CFraction c(-nume,deno);    return c;}void CFraction::display(){    cout<<nume<<"/"<<deno;}void CFraction::simplify(){    int m,d,r;    m=abs(nume);    d=abs(deno);    while((r=(m%d)))    {        m=d;d=r;    }    nume/=d;deno/=d;}CFraction CFraction::operator+(CFraction &c2){    CFraction c;    c.nume=nume*c2.deno+c2.nume*deno;    c.deno=deno*c2.deno;    c.simplify();    return c;}CFraction CFraction::operator-(CFraction &c2){    CFraction c;    c.nume=nume*c2.deno-c2.nume*deno;    c.deno=deno*c2.deno;    c.simplify();    return c;}CFraction CFraction::operator*(CFraction &c2){    CFraction c;    c.nume=nume*c2.nume;    c.deno=deno*c2.deno;    c.simplify();    return c;}CFraction CFraction::operator/(CFraction &c2){    CFraction c;    c.nume=nume*c2.deno;    c.deno=deno*c2.nume;    c.simplify();    return c;}bool CFraction::operator>(CFraction &c2){    if(nume*c2.deno>c2.nume*deno)        return true;    return false;}bool CFraction::operator<(CFraction &c2){    if(nume*c2.deno<c2.nume*deno)        return true;    return false;}bool CFraction::operator==(CFraction &c2){    if(nume*c2.deno==c2.nume*deno)        return true;    return false;}bool CFraction::operator>=(CFraction &c2){    return !((*this)<c2);}bool CFraction::operator<=(CFraction &c2){    return !((*this)>c2);}bool CFraction::operator!=(CFraction &c2){    return !((*this)==c2);}int main(){    CFraction c1,c2,c;    cin>>c1>>c2;    cout<<"c1="<<c1<<endl;    cout<<"c2="<<c2<<endl;    c=-c1;    cout<<"-c1="<<c<<endl;    c=~c1;    cout<<"~c1="<<c<<endl;    cout<<endl;    c=c1+c2;    cout<<"c1+c2="<<c;    c=c1-c2;    cout<<endl;    cout<<"c1-c2="<<c;    cout<<endl;    c=c1*c2;    cout<<"c1*c2="<<c;    cout<<endl;    c=c1/c2;    cout<<"c1/c2="<<c;    cout<<endl;    if(c1>c2) cout<<"c1>c2"<<endl;    if(c1<c2) cout<<"c1<c2"<<endl;    if(c1==c2) cout<<"c1==c2"<<endl;    if(c1>=c2) cout<<"c1>=c2"<<endl;    if(c1<=c2) cout<<"c1<=c2"<<endl;    if(c1!=c2) cout<<"c1!=c2"<<endl;    return 0;}

运行结果：

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