第9周项目3-分数类中的运算符重载续（2）

/*。*Copyright(c)2014,烟台大学计算机学院*All right reserved,*文件名：test.cpp*作者：毕玉堂*完成日期：2015年5月17日*版本号：v1.0*问题描述：*输入描述：*程序输出：*/#include <iostream>#include<Cmath>#include<cstdlib>using namespace std;int gcd(int m, int n);class CFraction{private:    int nume;  // 分子    int deno;  // 分母public:    friend istream& operator>>(istream &,CFraction &);    friend ostream& operator<<(ostream &,const CFraction &);    CFraction(int nu=0,int de=1):nume(nu),deno(de){}   //构造函数，初始化用    void set(int nu=0,int de=1);//置值，改变值时用    CFraction operator+(const CFraction &c);    CFraction operator-(const CFraction &c);    CFraction operator*(const CFraction &c);    CFraction operator/(const CFraction &c);    bool operator>(const CFraction &c);    bool operator<(const CFraction &c);    bool operator==(const CFraction &c);    bool operator!=(const CFraction &c);    bool operator>=(const CFraction &c);    bool operator<=(const CFraction &c);    void input();               //按照"nu/de"的格式，如"5/2"的形式输入    void simplify();            //化简（使分子分母没有公因子）    void amplify(int n);        //放大n倍，如2/3放大5倍为10/3    void output(int style);        //输出：以8/6为例，style为0时，原样输出8/6；                            //style为1时，输出化简后形式4/3；                            //style为2时，输出1(1/3)形式，表示一又三分之一；                            //style为3时，用小数形式输出，如1.3333；                            //默认方式0    CFraction operator+();//取正    CFraction operator-();//求反    CFraction operator~();//求倒数};void CFraction::set(int nu,int de){    if(de!=0)    {        nume=nu;        deno=de;    }}CFraction CFraction::operator+(const CFraction &c){    CFraction a;    a.nume=nume*c.deno+c.nume*deno;    a.deno=deno*c.deno;    a.simplify();    return a;}CFraction CFraction::operator-(const CFraction &c){    CFraction a;    a.nume=nume*c.deno-c.nume*deno;    a.deno=deno*c.deno;    a.simplify();    return a;}CFraction CFraction::operator*(const CFraction &c){    CFraction a;    a.nume=nume*c.nume;    a.deno=deno*c.deno;    a.simplify();    return a;}CFraction CFraction::operator/(const CFraction &c){    CFraction a;    a.nume=nume*c.deno;    a.deno=deno*c.nume;    a.simplify();    return a;}bool CFraction::operator>(const CFraction &c){   if((nume*c.deno>c.nume*deno&&deno*c.deno>0)||(nume*c.deno<c.nume*deno&&deno*c.deno<0))        return true;   return false;}bool CFraction::operator<(const CFraction &c){   if((nume*c.deno<c.nume*deno&&deno*c.deno>0)||(nume*c.deno>c.nume*deno&&deno*c.deno<0))        return true;   return false;}bool CFraction::operator==(const CFraction &c){   if(*this!=c)        return false;   return true;}bool CFraction::operator!=(const CFraction &c){   if(*this>c||*this<c)        return true;   return false;}bool CFraction::operator>=(const CFraction &c){   if(*this<c)        return false;   return true;}bool CFraction::operator<=(const CFraction &c){   if(*this>c)        return false;   return true;}istream &operator>>(istream &in,CFraction &x){    char ch;    while(1)    {        cin>>x.nume>>ch>>x.deno;        if (x.deno==0)            cerr<<"分母为0, 请重新输入\n";        else if(ch!='/')            cerr<<"格式错误（形如m/n）! 请重新输入\n";        else            break;    }    return cin;}ostream& operator<<(ostream &out,const CFraction &x){    out<<x.nume<<"/"<<x.deno<<endl;    return out;}void CFraction::simplify(){    int n=gcd(deno, nume);    deno/=n;     // 化简    nume/=n;}// 求m，n的最大公约数int gcd(int m, int n) //这个函数可以定义为类的成员函数，也可以为一般函数{    int r;    while(n!=0)    {        r=m%n;        m=n;        n=r;    }    return m;}void CFraction::amplify(int n){    nume*=n;}CFraction CFraction::operator+(){   CFraction c;   if(nume<0&&deno>0)   {      c.nume=-nume;      c.deno=deno;   }   else if(nume>0&&deno<0)   {       c.nume=nume;       c.deno=-deno;   }   else   {       c.nume=nume;       c.deno=deno;   }   return c;}CFraction CFraction::operator-(){    CFraction c;    c.nume=-nume;    c.deno=deno;    return c;}CFraction CFraction::operator~(){    CFraction c;    c.nume=deno;    c.deno=nume;    return c;}int main(){    CFraction x,y,s;    cin>>x>>y;    s=x+y;    cout<<"x+y=";    cout<<s;    s=x-y;    cout<<"x-y=";    cout<<s;    s=x*y;    cout<<"x*y=";    cout<<s;    s=x/y;    cout<<"x/y=";    cout<<s;    cout<<x;    if (x>y) cout<<"大于"<<endl;    if (x<y) cout<<"小于"<<endl;    if (x==y) cout<<"等于"<<endl;    cout<<y;    cout<<endl;    s=+y;    cout<<"y取正为:";    cout<<s;    s=-y;    cout<<"y的相反数为：";    cout<<s;    s=~x;    cout<<"x的倒数为：";    cout<<s;    return 0;}

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