bash regrex operator =~

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If you're using a recent bash (v3+) suggest bash regex comparison operator =~, i.e.

if [[ "$HOST" =~ ^user.* ]]; then    echo "yes"

fi

To match this or that in a regex use |, i.e.

if [[ "$HOST" =~ ^user.*|^host1 ]]; then    echo "yes"fi

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The =~ Regular Expression matching operator within a double brackets test expression. (Perl has a similar operator.)
#!/bin/bashvariable="This is a fine mess."echo "$variable"# Regex matching with =~ operator within [[ double brackets ]].if [[ "$variable" =~ T.........fin*es* ]]# NOTE: As of version 3.2 of Bash, expression to match no longer quoted.then  echo "match found"      # match foundfi
Or, more usefully:
#!/bin/bashinput=$1if [[ "$input" =~ "[0-9][0-9][0-9]-[0-9][0-9]-[0-9][0-9][0-9][0-9]" ]]#                 ^ NOTE: Quoting not necessary, as of version 3.2 of Bash.# NNN-NN-NNNN (where each N is a digit).then  echo "Social Security number."  # Process SSN.else  echo "Not a Social Security number!"  # Or, ask for corrected input.fi

refer the link

http://tldp.org/LDP/abs/html/bashver3.html#REGEXMATCHREF

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