【leetcode c++】58 Length of Last Word

Length of Last Word

Given a string s consists ofupper/lower-case alphabets and empty space characters ' ', return the length oflast word in the string.

If the last word does not exist, return 0.

 

Note: A word is defined as a charactersequence consists of non-space characters only.

 

For example,

Given s = "Hello World",

return 5.

 

看起来不是很难，其实确实如此，我就直接在leetcode网页上写了。填一些坑就完事了。

两个坑，第一它允许尾空格，我们要忽略它。第二就是结束判断。

 

Leetcode的AcceptedSolutions Runtime Distribution（崩溃，58跟66的图一样，重新截——15-06-26）

 

源码：

int lengthOfLastWord(string s){string::iterator iter = s.end();int len = 0;bool start = false;while (s.begin() != iter){iter--;if (' ' != *iter){start = true;}if (start){if (' ' != *iter) len++;else return len;}}return len;}