[leetcode-58]Length of Last Word(c)

问题描述：
Given a string s consists of upper/lower-case alphabets and empty space characters ’ ‘, return the length of last word in the string.

If the last word does not exist, return 0.

Note: A word is defined as a character sequence consists of non-space characters only.

For example,
Given s = “Hello World”,
return 5.

分析：这道题很简单，只要从后向前，将空格过滤掉，然后如果没有了，直接返回0，然后再从后向前查找，当出现空格时，退出。返回计数。

代码如下：0ms

int lengthOfLastWord(char* s) {    int length = strlen(s);    int index = length-1;    while(index>=0&&s[index]==' ')        index--;    if(index<0)        return 0;    int count = 0;    while(index>=0&&s[index]!=' ')    {        count++;        index--;    }    return count;}