LeetCode_67---Add Binary

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Given two binary strings, return their sum (also a binary string).

For example,
a = "11"
b = "1"
Return "100".

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Math String

翻译：

Code:

/** *  */package From61;import java.util.Arrays;/** * @author MohnSnow * @time 2015年6月29日 下午1:40:25 *  */public class LeetCode67 {/** * @param argsmengdx *            -fnst *///360msAC----一次性提交通过public static String addBinary(String a, String b) {int a_len = a.length();int b_len = b.length();if (a_len == 0) {return b;} else if (b_len == 0) {return a;}int len = Math.max(a_len, b_len);int[] temp = new int[len];int tempInt = 0;for (int i = 1; i <= len; i++) {temp[len - i] = ((a_len - i) >= 0 ? a.charAt(a_len - i) - '0' : 0) + ((b_len - i) >= 0 ? b.charAt(b_len - i) - '0' : 0) + tempInt;System.out.println("temp[len - i]: " + temp[len - i]);if (temp[len - i] > 1) {tempInt = 1;temp[len - i] = temp[len - i] - 2;} else {tempInt = 0;}}StringBuffer result = new StringBuffer();if (tempInt == 1) {result.append("1");}for (int i = 0; i < len; i++) {result.append(temp[i]);}return result.toString();}//https://leetcode.com/discuss/35278/short-ac-solution-in-java-with-explanation//优化public String addBinary1(String a, String b) {StringBuilder sb = new StringBuilder();int i = a.length() - 1, j = b.length() - 1, carry = 0;while (i >= 0 || j >= 0) {int sum = carry;if (j >= 0)sum += b.charAt(j--) - '0';if (i >= 0)sum += a.charAt(i--) - '0';sb.append(sum % 2);carry = sum / 2;}if (carry != 0)sb.append(carry);return sb.reverse().toString();}public static void main(String[] args) {String a = "1";String b = "101";System.out.println("addBinary: " + addBinary(a, b));}}

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