翻转

1.翻转整型数字（翻转前为n，翻转后为t）

while(n)    {        t=t*10+n%10;        n/=10;    }

2.翻转数组

void rever_char(char c[],int n){ char temp; int i,j = n-1,m = (n-1)/2; for(i = 0; i <= m; i++) {  j = n-1-i;  temp = c[i];  c[i] = c[j];  c[j] = temp; }}

3，指针翻转数组

void reversal(int *a,int len)  {      if (len<2)          return;      //用指针实现      int *left=a,*right=a+len-1,temp;      do      {          temp = *left;          *left = *right;          *right = temp;      }while (++left < --right);      /*while (left++ <= right--)//指针的第二种写法     {         temp = *left;         *left = *right;         *right = temp;     }     //用数组实现     int end=len/2,tmp,j;     for (int i=0;i<end;++i)     {         tmp = a[i];         j = len -1 - i;         a[i] = a[j];         a[j] = tmp;     }*/  }  

转载请注明出处：http://blog.csdn.net/jinjide_ajin/article/details/46834737