关于void

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#include<iostream>#include<cmath>#include<cstdio>using namespace std;long A[100010],n;long k1,k2;long sep(int x,int y,int k){int mid = x + (y-x)/2;long i = x,j = y,key = A[mid];A[mid] = A[x];while(i < j){while(i < j && A[j] >= key)  j--;A[i] = A[j];while(i < j && A[i] < key)  i++;A[j] = A[i];}A[i] = key;if(i == k) return A[i];if(i > k) sep(x,i-1,k);else if(i < k) sep(i+1,y,k);}/*bool*/void prime(){int m = k2 - k1;if(m < 2){printf("NO\n");return;}else if(m == 2){printf("YES\n");printf("%d\n", m);return ;}else if(m > 2){for(int i = 2; i <= int(sqrt(m))+1; i++)  if(m%i == 0)  {  printf("NO\n");printf("%d\n", m);  return ;  }printf("YES\n");printf("%d\n", m);return;}/*int i;if(m<=1) return false;for(i=2; i*i<=m; i++)  if(m%i==0)    return false;    return true;*/}int main(){int k,i;cin>>n>>k;for(i = 1; i <= n; i++)  cin>>A[i];k1 = sep(1,n,k);k2 = sep(1,n,n-k+1);prime();/*int m = k2 - k1;if(prime())  printf("YES\n");else  printf("NO\n");printf("%d\n", m);*/return 0;}

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void输出是否会有溢出？若在wikioi上，注释部分可AC，而在void函数内输出则WA

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