UVA10340-All in all

Description

You have devised a new encryption technique which encodes a message by inserting between its characters randomly generated strings in a clever way. Because of pending patent issues we will not discuss in detail how the strings are generated and inserted into the original message. To validate your method, however, it is necessary to write a program that checks if the message is really encoded in the final string. Given two strings s and t, you have to decide whether s is a subsequence of t, i.e. if you can remove characters from t such that the concatenation of the remaining characters is s.

Input

The input contains several testcases. Each is specified by two strings s, t of alphanumeric ASCII characters separated by whitespace. Input is terminated by EOF.

Output

For each test case output, if s is a subsequence of t.

Sample Input

sequence subsequence 

person compression 

VERDI vivaVittorioEmanueleReDiItalia 

caseDoesMatter CaseDoesMatter

Sample Output

Yes 

No 

Yes 

No

注意遍历过程中t与s的顺序，并不是在t中找到s的字符即可，还要有s的顺序。

代码如下：

#include <stdio.h>#include <stdlib.h>#include <string.h>#define Maxn 100010char s[Maxn],t[Maxn];int main(){    int i,j,m,c;    while(scanf("%s%s",s,t)!=-1)    {        m=0;c=0;j=0;        for(i=0;i<strlen(s);i++)        {j=m;            for(;j<strlen(t);)            {            j=m;                if(s[i]==t[j])                {                    m++;c++;break;                }                m++;            }        }        if(c==strlen(s))            printf("Yes\n");        else            printf("No\n");    }    return 0;}