1008Maya Calendar

Maya Calendar

Time Limit: 1000ms   Memory limit: 10000K  有疑问？点这里^_^

题目描述

 During his last sabbatical, professor M. A. Ya made a surprising discovery about the old Maya calendar. From an old knotted message, professor discovered that the Maya civilization used a 365 day long year, calledHaab, which had 19 months. Each of the first 18 months was 20 days long, and the names of the months werepop, no, zip, zotz, tzec, xul, yoxkin, mol, chen, yax, zac, ceh, mac, kankin, muan, pax, koyab, cumhu. Instead of having names, the days of the months were denoted by numbers starting from 0 to 19. The last month of Haab was calleduayet and had 5 days denoted by numbers 0, 1, 2, 3, 4. The Maya believed that this month was unlucky, the court of justice was not in session, the trade stopped, people did not even sweep the floor.

For religious purposes, the Maya used another calendar in which the year was calledTzolkin (holly year). The year was divided into thirteen periods, each 20 days long. Each day was denoted by a pair consisting of a number and the name of the day. They used 20 names:imix, ik, akbal, kan, chicchan, cimi, manik, lamat, muluk, ok, chuen, eb, ben, ix, mem, cib, caban, eznab, canac, ahau and 13 numbers; both in cycles.

Notice that each day has an unambiguous description. For example, at the beginning of the year the days were described as follows:

1 imix, 2 ik, 3 akbal, 4 kan, 5 chicchan, 6 cimi, 7 manik, 8 lamat, 9 muluk, 10 ok, 11 chuen, 12 eb, 13 ben, 1 ix, 2 mem, 3 cib, 4 caban, 5 eznab, 6 canac, 7 ahau, and again in the next period 8 imix, 9 ik, 10 akbal . . .

Years (both Haab and Tzolkin) were denoted by numbers 0, 1, : : : , where the number 0 was the beginning of the world. Thus, the first day was:

• Haab: 0. pop 0
• Tzolkin: 1 imix 0

  Help professor M. A. Ya and write a program for him to convert the dates from the Haab calendar to the Tzolkin calendar. 

输入

The date in Haab is given in the following format:

NumberOfTheDay. Month Year

The first line of the input file contains the number of the input dates in the file. The next n lines contain n dates in the Haab calendar format, each in separate line. The year is smaller then 5000. 

输出

The date in Tzolkin should be in the following format:

Number NameOfTheDay Year

The first line of the output file contains the number of the output dates. In the next n lines, there are dates in the Tzolkin calendar format, in the order corresponding to the input dates. 

示例输入

310. zac 00. pop 010. zac 1995

示例输出

33 chuen 01 imix 09 cimi 2801

提示

#include<iostream>#include<cstring>#include<cstdio>using namespace std;int main(){    string s[19]= {"pop","no","zip","zotz","tzec","xul","yoxkin","mol","chen","yax",                   "zac","ceh","mac","kankin","muan","pax","koyab","cumhu","uayet"                  };    string ss[20]= {"ahau","imix","ik","akbal","kan","chicchan","cimi","manik","lamat","muluk",                    "ok","chuen","eb","ben","ix","mem","cib","caban","eznab","canac"                   };    int year,day;    string month;    int sum[1000000];    int n;    while(cin>>n)    {        for(int i=1; i<=n; i++)        {            scanf("%d.",&day);            cin>>month>>year;            for(int j=0; j<19; j++)                if(month==s[j])                {                    sum[i]=day+1+j*20+year*365;//将时间化成具有的公共部分即总天数；                    break;                }        }        cout<<n<<endl;        for(int i=1; i<=n; i++)        {            int a=(sum[i]-1)/260; //求年，注意存在0年                        sum[i]-=a*260;        //在某一年剩余的天数                   int b=sum[i]%13;                  if(b==0)              //存在13                b=13;             cout<<b<<" ";            for(int j=0; j<20; j++)            {                if(sum[i]%20==j)     //整除时应为20时期即"ahau"                    cout<<ss[j]<<" ";            }            cout<<a<<endl;        }    }}

以后做题要自己深入思考，多举几个特殊例子这样就不会错那么多次了