[leetcode-33]Search in Rotated Sorted Array(C)
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问题描述:
Suppose a sorted array is rotated at some pivot unknown to you beforehand.
(i.e., 0 1 2 4 5 6 7 might become 4 5 6 7 0 1 2).
You are given a target value to search. If found in the array return its index, otherwise return -1.
You may assume no duplicate exists in the array.
分析：这个题确定没有bug？？？
代码如下：0ms
int search(int* nums, int numsSize, int target) { int i; for(i = 0;i<numsSize;i++){ if(nums[i]==target) break; } if(i>=numsSize) return -1; return i;} 0 0
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