Clique in the Divisibility Graph

F. Clique in the Divisibility Graph

time limit per test

1 second

memory limit per test

256 megabytes

input

standard input

output

standard output

As you must know, the maximum clique problem in an arbitrary graph is NP-hard. Nevertheless, for some graphs of specific kinds it can be solved effectively.

Just in case, let us remind you that a clique in a non-directed graph is a subset of the vertices of a graph, such that any two vertices of this subset are connected by an edge. In particular, an empty set of vertexes and a set consisting of a single vertex, are cliques.

Let's define a divisibility graph for a set of positive integers A = {a1, a2, ..., an} as follows. The vertices of the given graph are numbers from set A, and two numbers ai and aj (i ≠ j) are connected by an edge if and only if either ai is divisible by aj, or aj is divisible by ai.

You are given a set of non-negative integers A. Determine the size of a maximum clique in a divisibility graph for set A.

Input

The first line contains integer n (1 ≤ n ≤ 106), that sets the size of set A.

The second line contains n distinct positive integers a1, a2, ..., an (1 ≤ ai ≤ 106) — elements of subset A. The numbers in the line follow in the ascending order.

Output

Print a single number — the maximum size of a clique in a divisibility graph for set A.

Sample test(s)

input

83 4 6 8 10 18 21 24

output

3

Note

In the first sample test a clique of size 3 is, for example, a subset of vertexes {3, 6, 18}. A clique of a larger size doesn't exist in this graph.

这题不难，就是优化时间上有点难度。可以写出完成任务的代码，但是不符合条件，所以都是白费功夫。之后再去看看别人写的代码，然后再自己重写了一遍就AC了。

#include<iostream>#include<algorithm>#include<cstring>#include<string>#include<cstdio>using namespace std;#define T 1000100int n,dp[T],i,j,ma=0,k;int main(){//freopen("input.txt","r",stdin);scanf("%d",&n);for(i=0;i<n;++i){scanf("%d",&k);ma = max(ma,++dp[k]);for(j=2*k;j<T;j+=k){dp[j] = max(dp[j],dp[k]);}}printf("%d\n",ma);return 0;}