Hduuoj1034【水题】

/*Candy Sharing GameTime Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 3782    Accepted Submission(s): 2359Problem DescriptionA number of students sit in a circle facing their teacher in the center. Each student initially has an even number of pieces of candy. When the teacher blows a whistle, each student simultaneously gives half of his or her candy to the neighbor on the right. Any student, who ends up with an odd number of pieces of candy, is given another piece by the teacher. The game ends when all students have the same number of pieces of candy. Write a program which determines the number of times the teacher blows the whistle and the final number of pieces of candy for each student from the amount of candy each child starts with.InputThe input may describe more than one game. For each game, the input begins with the number N of students, followed by N (even) candy counts for the children counter-clockwise around the circle. The input ends with a student count of 0. Each input number is on a line by itself.OutputFor each game, output the number of rounds of the game followed by the amount of candy each child ends up with, both on one line.Sample Input6362222211222018161412108642424680 Sample Output15 1417 224 8HintThe game ends in a finite number of steps because:1. The maximum candy count can never increase.2. The minimum candy count can never decrease.3. No one with more than the minimum amount will ever decrease to the minimum.4. If the maximum and minimum candy count are not the same, at least one student with the minimum amount must have their count increase.SourceGreater New York 2003 RecommendWe have carefully selected several similar problems for you:  1035 1037 1038 1036 1062 */#include<stdio.h>#include<stdlib.h>#include<malloc.h>int main(){int i, j, k, n;while(scanf("%d", &n) != EOF && n){int * a = (int *)malloc(n * sizeof(int));int * b = (int *)malloc(n * sizeof(int));for(i = 0; i < n; ++i)scanf("%d", &a[i]);int cnt = 0;while(1){for(i = 1; i < n; ++i)if(a[i] != a[0])break;if(i == n)break;for(i = 0; i < n; ++i){a[i]>>=1;b[i] = a[i];}for(i = 0; i < n; ++i){if(i == 0)a[i] += b[n-1];elsea[i] += b[i-1];if(a[i] & 1)a[i]++;}cnt++;}printf("%d %d\n", cnt, a[0]); free(a);free(b);} return 0;} 

题意：老师在中间，学生围着老师成一个圈，刚开始每个学生手里都有偶数颗糖，老师每吹一次口哨，每一个学生都要将手里的一半糖给右手边的同学，当这一轮结束后若有的学生手里的糖的个数是奇数你，那么老师会给这个学生补上一课糖，求经过多少轮后每个学生手里的糖个数一样，并且输出糖的个数。

思路：开2个数组，a数组模拟现有的糖，b数组代表过程中每个学生的手里的一半糖然后每个学生按照过程累加就是了。每过一轮进行一次判断，直至相同。