HDOJ2222Keywords Search【AC自动机模板题】
来源:互联网 发布:淘宝看不到对方评论 编辑:程序博客网 时间:2024/04/27 18:38
Keywords Search
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 44074 Accepted Submission(s): 13848
Problem Description
In the modern time, Search engine came into the life of everybody like Google, Baidu, etc.
Wiskey also wants to bring this feature to his image retrieval system.
Every image have a long description, when users type some keywords to find the image, the system will match the keywords with description of image and show the image which the most keywords be matched.
To simplify the problem, giving you a description of image, and some keywords, you should tell me how many keywords will be match.
Wiskey also wants to bring this feature to his image retrieval system.
Every image have a long description, when users type some keywords to find the image, the system will match the keywords with description of image and show the image which the most keywords be matched.
To simplify the problem, giving you a description of image, and some keywords, you should tell me how many keywords will be match.
Input
First line will contain one integer means how many cases will follow by.
Each case will contain two integers N means the number of keywords and N keywords follow. (N <= 10000)
Each keyword will only contains characters 'a'-'z', and the length will be not longer than 50.
The last line is the description, and the length will be not longer than 1000000.
Each case will contain two integers N means the number of keywords and N keywords follow. (N <= 10000)
Each keyword will only contains characters 'a'-'z', and the length will be not longer than 50.
The last line is the description, and the length will be not longer than 1000000.
Output
Print how many keywords are contained in the description.
Sample Input
15shehesayshrheryasherhs
Sample Output
3
Author
Wiskey
AC-自动机模板题暨我的第一道AC-自动机题
AC自动机参考资料:AC自动机讲解 邝斌博客 :邝斌博客
#include<cstdio>#include<cstdlib>#include<cstring>#include<queue>using namespace std;struct Node{int next[500010][26],fail[500010],end[500010];int L,root;int newNode(){for(int i=0;i<26;++i){next[L][i]=-1;}end[L++]=0;return L-1;}void init(){L=0;root=newNode();}void insert(char *s){int i,len=strlen(s);int now=root;for(i=0;i<len;++i){if(next[now][s[i]-'a']==-1){next[now][s[i]-'a']=newNode();}now=next[now][s[i]-'a'];}end[now]++;}void build(){fail[root]=root;queue<int>Q;for(int i=0;i<26;++i){if(next[root][i]==-1){next[root][i]=root;}else{fail[next[root][i]]=root;Q.push(next[root][i]);}}while(!Q.empty()){int now=Q.front();Q.pop();for(int i=0;i<26;++i){if(next[now][i]==-1){next[now][i]=next[fail[now]][i];}else{fail[next[now][i]]=next[fail[now]][i];Q.push(next[now][i]);}}}}int query(char *s){int ans=0;int now=root;int len=strlen(s);for(int i=0;i<len;++i){now=next[now][s[i]-'a'];int temp=now;while(temp!=root){ans+=end[temp];end[temp]=0;temp=fail[temp];}}return ans;}};char str[1000010];Node ac;int main(){int i,j,t,n;scanf("%d",&t);while(t--){scanf("%d",&n);ac.init();while(n--){scanf("%s",str);ac.insert(str);}ac.build();scanf("%s",str);printf("%d\n",ac.query(str));}return 0;}
0 0
- HDOJ2222Keywords Search【AC自动机模板题】
- HDU2222 Keywords Search AC自动机模板题
- HDU2222 Keywords Search(AC自动机模板题)
- hdu2222Keywords Search AC自动机模板题
- hdu2222 Keywords Search(AC自动机模板题)
- Keywords Search(AC自动机模板题)
- HDU2222 Keywords Search 【AC自动机模板题】
- hdu2222Keywords Search(AC自动机模板题)
- HDU 2222 Keywords Search(AC自动机模板题)
- hdu 2222 Keywords Search(AC自动机模板题)
- HDU 2222 Keywords Search (AC自动机模板题)
- hdu 2222 Keywords Search(AC自动机模板题)
- poj 2222 Keywords Search,AC自动机模板题
- HDU 2222 Keywords Search AC自动机模板题
- hdu 2222 Keywords Search(ac自动机模板题)
- hdu 2222 Keywords Search AC自动机模板题
- HDU 2222 Keywords Search(AC自动机模板题)
- HDU 2222 Keywords Search (AC自动机模板题)
- Linux电源管理(7)_Wakeup events framework
- JAVA学习之《JAVA核心技术》 学习笔记
- 线程安全
- JAR包引用其它JAR包的classpath问题
- jsonp 跨域问题
- HDOJ2222Keywords Search【AC自动机模板题】
- UDP的键盘录入
- Can not find the tag library descriptor for "http://java.sun.com/jsp/jstl/core
- uva 10160Servicing Stations
- Android SVG动画PathView源码解析与使用教程(API 14)
- hdu 1711(kmp算法)
- 4.8 自定义下拉菜单模式——Spinner与setDropDownViewResource
- Linux电源管理(8)_Wakeup count功能
- CZY的组合数烦恼