简单测试一下go(golang) 和libtask 协程的切换效率

来源：互联网发布：golang syscall说明编辑：程序博客网时间：2024/05/31 00:39

简单测试一下go(golang)和libtask协程的切换效率, libtask一个C语言的协程库，是go语言的前身
很早期的原型. 测试机器是我的mac air 安装的centos虚拟机(只有一个核), 代码没有采用任何优化，
只是使用默认配置

测试结论：
golang 切换100w次需要 295ms
libtask 切换100w次需要1446ms

golang 测试代码:

package mainimport (   "fmt"   "runtime"   "time"   )var i int = 0func test(){for{i++if i >1000000{fmt.Printf("end switch \n")break}else{//fmt.Printf(" in test i:%d  \n", i)}runtime.Gosched()}}func main(){fmt.Printf("GOMAXPROCS :%d \n",runtime.GOMAXPROCS(1))tv1 := time.Now().UnixNano()go test()// in main goroutinetest()tv2 := time.Now().UnixNano()usetime := (tv2 - tv1)/1000000fmt.Printf("use time:  %dms \n", usetime)fmt.Printf("end main \n")}

libtask 测试代码:

#include <stdio.h>#include <string.h>#include <errno.h>#include <unistd.h>#include <stdlib.h>#include <task.h>#include<sys/time.h>extern int tasknswitch;enum { STACK = 32768 };int i = 0;struct timeval tv1, tv2;voidtestswitch(void *v){  int ms;  while(1)  {  i++;  if( i< 1000000)  {      //printf("int task i:%d \n", i);      taskyield();  }  else  {       //  chansendul(c, 0);      //taskexitall(0);      gettimeofday(&tv2,NULL);          ms =  ((tv2.tv_sec - tv1.tv_sec)*1000000 + (tv2.tv_usec - tv1.tv_usec))/1000;          printf("time use %d\n ", ms);          printf("task swithch %d \n", tasknswitch);      taskexitall(0);    }   }}voidtaskmain(int argc, char **argv){  int  n;//c = chancreate(sizeof(unsigned long), 0);  gettimeofday(&tv1, NULL);//for(i=1; i<; i++){taskcreate(testswitch, 0, STACK);//}    testswitch(NULL);}

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