pat(A) 1002. A+B for Polynomials (一元多项式的表示及相加)
来源:互联网 发布:windows 32位升级64位 编辑:程序博客网 时间:2024/06/05 12:06
代码:
#include<cstdio>#include<cstring>using namespace std;int main(){ double a[1005]; int k; while(scanf("%d",&k)==1) { memset(a,0,sizeof(a)); int exp; double c; while(k--) { scanf("%d%lf",&exp,&c); a[exp]+=c; } scanf("%d",&k); while(k--) { scanf("%d%lf",&exp,&c); a[exp]+=c; } int cnt=0; for(int i=1004; i>=0; i--) { if(a[i]!=0.0) cnt++; } printf("%d",cnt); cnt=0; for(int i=1004; i>=0; i--) { if(a[i]!=0) { printf(" %d %.1lf",i,a[i]); } } printf("\n"); } return 0;}
0 0
- pat(A) 1002. A+B for Polynomials (一元多项式的表示及相加)
- [PAT甲级]1002. A+B for Polynomials (25)(求两个多项式的和)
- PAT A 1002. A+B for Polynomials
- PAT-A 1002.A+B for Polynomials
- PAT-A-1002. A+B for Polynomials
- PAT 1002 . A+B for Polynomials (25)多项式加法
- 【PAT】1002. A+B for Polynomials (25)
- PAT 1002. A+B for Polynomials
- PAT 1002. A+B for Polynomials (25)
- PAT-1002. A+B for Polynomials(Map)
- [PAT]1002. A+B for Polynomials (25)
- pat 1002. A+B for Polynomials (25)
- PAT 1002. A+B for Polynomials (25)
- PAT 1002. A+B for Polynomials (25)
- PAT 1002. A+B for Polynomials
- PAT 1002. A+B for Polynomials (25)
- PAT 1002. A+B for Polynomials (25)
- PAT 1002. A+B for Polynomials (25)
- eclipse下web开发步骤
- MetaSploit framework基础知识
- 适配器模式
- 1080. Graduate Admission (30)
- java登录程序用户密码5分钟内输错3次锁定用户账号一天的实现
- pat(A) 1002. A+B for Polynomials (一元多项式的表示及相加)
- 【Shader】Shader名词详解
- 黑马程序员——JAVA高新技术——反射
- abstract class 和 interface 区别
- HDOJ 1874 畅通工程续 (最短路 Dijkstra && SPFA && Floyd)
- ExtJs 复杂的panel设置控件只读
- 再读《C和指针》(笔记2)
- TFS权限设置学习笔记(1)
- Git 操作指南