02-线性结构4. Pop Sequence (25)

时间限制

100 ms

内存限制

65536 kB

代码长度限制

8000 B

判题程序

Standard

作者

CHEN, Yue

Given a stack which can keep M numbers at most. Push N numbers in the order of 1, 2, 3, ..., N and pop randomly. You are supposed to tell if a given sequence of numbers is a possible pop sequence of the stack. For example, if M is 5 and N is 7, we can obtain 1, 2, 3, 4, 5, 6, 7 from the stack, but not 3, 2, 1, 7, 5, 6, 4.

Input Specification:

Each input file contains one test case. For each case, the first line contains 3 numbers (all no more than 1000): M (the maximum capacity of the stack), N (the length of push sequence), and K (the number of pop sequences to be checked). Then K lines follow, each contains a pop sequence of N numbers. All the numbers in a line are separated by a space.

Output Specification:

For each pop sequence, print in one line "YES" if it is indeed a possible pop sequence of the stack, or "NO" if not.

Sample Input:

5 7 51 2 3 4 5 6 73 2 1 7 5 6 47 6 5 4 3 2 15 6 4 3 7 2 11 7 6 5 4 3 2

Sample Output:

YESNONOYESNO

好几个月没写数据结构程序了，显得生疏，网查大侠方法，模拟整个进栈，检测，出栈的过程，这个问题就能慢慢解决了~

#include<iostream>#include<stack>using namespace std;int main(){int M,N,K;//freopen("C:\\Users\\Jimko\\Desktop\\cin.txt","r",stdin);cin>>M>>N>>K;for(int i=0;i<K;i++){stack<int> s;bool flag = true;int t=1;for(int j=0;j<N;j++){//测试数据逐个输入 int num;cin>>num;if(flag){while(s.empty() || s.top() != num){s.push(t);if(s.size()>M){flag = false;break;}t++;//有序进栈 }if(flag && s.size()>=1 && s.top()==num)//出栈条件 s.pop();}}if(flag)printf("YES\n");elseprintf("NO\n");} return 0;}