Leetcode: Sum Root to Leaf Numbers

来源:互联网 发布:赛迪斯杨数据 编辑:程序博客网 时间:2024/06/06 23:50

Question

Given a binary tree containing digits from 0-9 only, each root-to-leaf path could represent a number.

An example is the root-to-leaf path 1->2->3 which represents the number 123.

Find the total sum of all root-to-leaf numbers.

For example,

1

/ \
2 3
The root-to-leaf path 1->2 represents the number 12.
The root-to-leaf path 1->3 represents the number 13.

Return the sum = 12 + 13 = 25.

Show Tags
Show Similar Problems

Analysis

think of each subtree as a new tree.


Solution

Pass at the first time

# Definition for a binary tree node.# class TreeNode(object):#     def __init__(self, x):#         self.val = x#         self.left = None#         self.right = Noneclass Solution(object):    def sumNumbers(self, root):        """        :type root: TreeNode        :rtype: int        """        total = 0        if root==None:            return total        return self.helper(root, root.val, total)    def helper(self, curnode, up2value, total):        if curnode.left==None and curnode.right==None:            return total + up2value        if curnode.left!=None:            total = self.helper(curnode.left, up2value*10+curnode.left.val, total)        if curnode.right!=None:            total = self.helper(curnode.right, up2value*10+curnode.right.val, total)        return total
0 0
原创粉丝点击