leetcode: Add Digits

Given a non-negative integer num, repeatedly add all its digits until the result has only one digit.

For example:

Given num = 38, the process is like: 3 + 8 = 11, 1 + 1 = 2. Since 2 has only one digit, return it.

Follow up:
Could you do it without any loop/recursion in O(1) runtime?

题目描述：给出一个数组，不断地分割数字，直到这个数字是一个数字为止。题目很简单，直接上代码。

代码实现：

class Solution {public:    int addDigits(int num) {        while(num<10)        {            return num;        }        int s=0;        while(num>0)        {            s+=num%10;            num/=10;        }        return addDigits(s);    }};