Spring MVC ParameterizableViewController example

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In general, to return a view or page in Spring MVC application, you need to create a class, which extends the AbstractController , and return a ModelAndView() object.

public class WelcomeController extends AbstractController{    @Override    protected ModelAndView handleRequestInternal(HttpServletRequest request,        HttpServletResponse response) throws Exception {        ModelAndView model = new ModelAndView("WelcomePage");        return model;    }}

In the bean configuration file, declared a ControllerClassNameHandlerMapping to auto detect the mapping.

<bean  class="org.springframework.web.servlet.mvc.support.ControllerClassNameHandlerMapping" /><bean class="com.mkyong.common.controller.WelcomeController" />

But, don’t you think it’s too much configuration for a simple redirect task? Fortunately, Spring comes with ParameterizableViewController to simplify the above processes. With ParameterizableViewController, you don’t need to hard code the view name in the controller class anymore, instead, you put view name declarative through the ParameterizableViewController’s “viewName” property.

Note
The ParameterizableViewController is a subclass of AbstractController, and return a ModelAndView based on the “viewName” property, it’s purely a redirect class, nothing more, nothing less :)

ParameterizableViewController.java

public class ParameterizableViewController extends AbstractController{//...protected ModelAndView handleRequestInternal(    HttpServletRequest request, HttpServletResponse response)    throws Exception {    return new ModelAndView(getViewName());}

Tutorial

In this tutorial, it shows the use of ParameterizableViewController controller to do a page redirection in the Spring MVC application.

1. `ParameterizableViewController`

No controller class is required, just declared the ParameterizableViewController bean and specify the view name through the “viewName” property. Additionally, you have to define an explicit mapping for it.

<beans xmlns="http://www.springframework.org/schema/beans"    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"    xsi:schemaLocation="http://www.springframework.org/schema/beans     http://www.springframework.org/schema/beans/spring-beans-2.5.xsd">    <bean class="org.springframework.web.servlet.handler.SimpleUrlHandlerMapping">        <property name="mappings">            <props>                <prop key="/welcome.htm">welcomeController</prop>            </props>        </property>    </bean>   <bean name="welcomeController"             class="org.springframework.web.servlet.mvc.ParameterizableViewController">        <property name="viewName" value="WelcomePage" />   </bean>   <bean id="viewResolver"        class="org.springframework.web.servlet.view.InternalResourceViewResolver" >            <property name="prefix">              <value>/WEB-INF/pages/</value>            </property>            <property name="suffix">              <value>.jsp</value>            </property>    </bean></beans>

Define an explicit mapping is required.

<beans ...>//...<bean class="org.springframework.web.servlet.mvc.support.ControllerClassNameHandlerMapping" /><bean name="welcomeController"     class="org.springframework.web.servlet.mvc.ParameterizableViewController">    <property name="viewName" value="WelcomePage" /></bean>//...</beans>

In above snippet, are you expect a view name “welcome” will return a “WelcomePage”? Sorry, it’s not, you have to define an explicit mapping, because the ControllerClassNameHandlerMapping won’t generate a mapping for any built-in Spring MVC controller.

2. View

Just a simple JSP to display a head line.

WelcomePage.jsp.jsp

<html><body><h2>ParameterizableViewController Example</h2></body></html>

3. Demo

Access it via “http://localhost:8080/SpringMVC/welcome.htm“, the “welcome.htm” will return back a “/WEB-INF/pages/WelcomPage.jsp“.
SpringMVC-ParameterizableViewController-Example-1
其实就是一个只有一个方法的控制器现在不用自己写了，反正都跟ParameterizableViewController实现的功能一样，那就直接使用ParameterizableViewController类就行了。

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