【leetcode每日一题】203.Remove Linked List Elements
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题目:
Remove all elements from a linked list of integers that have value val.
Example
Given: 1 --> 2 --> 6 --> 3 --> 4 --> 5 --> 6, val = 6
Return: 1 --> 2 --> 3 --> 4 --> 5
解析:声明一个节点result,然后让它指向头结点。再声明两个节点,让它们分别指向前一个节点和当前节点。依次遍历链表,当找到要删除节点时,直接让前一节点指向当前节点的下一节点即可。最后函数返回result的下一节点。代码如下:
/** * Definition for singly-linked list. * struct ListNode { * int val; * ListNode *next; * ListNode(int x) : val(x), next(NULL) {} * }; */class Solution {public: ListNode* removeElements(ListNode* head, int val) { ListNode *result=new ListNode(0); result->next=head; ListNode *preNode=result; ListNode *currentNode=head; if(head==NULL) return head; while(currentNode!=NULL) { if(currentNode->val==val) { preNode->next=currentNode->next; currentNode=currentNode->next; } else { preNode=currentNode; currentNode=currentNode->next; } } return result->next; }};
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