C语言基础学习——第4天(数组)

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00array_define.c

#include <stdio.h>int main(void){    // 数组和指针都是复合类型, 它们从另外一种基础类型(基本类型, 结构类型)派生.    // 定义数组时,    // 1. 确定数组元素的类型.    // 2. 显式或隐式的确定数组的元素个数.    // 这里的 '[]' 是声明说明符号.    int ary[5];    int a[] = { 36, 48, 12, 6, -3 };    int i = 0;    printf("sizeof ary = %u, sizeof ary[0] = %u\n", sizeof(ary), sizeof(ary[0]));    printf("sizeof ary / sizeof ary[0] = %u\n", sizeof(ary) / sizeof(ary[0]));    printf("----------------------------------\n");    // 这里的 '[]' 是运算符, 索引访问运算符号.    for (i = 0; i < 5; i++)        printf("a[%d] = %d\n", i, a[i]);    // 越界 越界产生不确定的运行行为.    // a[5] = 4;    return 0;}运行结果:sizeof ary = 20, sizeof ary[0] = 4sizeof ary / sizeof ary[0] = 5----------------------------------a[0] = 36a[1] = 48a[2] = 12a[3] = 6a[4] = -3

01array_name.c

#include <stdio.h>int main(void){    int a[5] = { 36, 48, 12, 18, };    int b[5];    // 数组名代表数组首元素地址. 数组名是一个常量值.    // b = a; // 非法.    printf("a = %p, &a[0] = %p\n", a, &a[0]);    printf("a = %p, &a[1] = %p\n", a, &a[1]);    return 0;}运行结果:a = 0xbfaea908, &a[0] = 0xbfaea908a = 0xbfaea908, &a[1] = 0xbfaea90c

02array_arg.c

#include <stdio.h>// 当数组作为函数参数时, 退化为一个指针.// 即当作为函数参数时, 如下形参等价.// --> int a[10] == int a[] == int *avoid test(int a[10]){    printf("in test, sizeof a = %u\n", sizeof(a));}void rand_a(int a[], int len){    int i = 0;    for (i = 0; i < len; i++)        a[i] = rand() % 100;}void print_a(int *a, int len){    int i = 0;    for (i = 0; i < len; i++)        printf("%d ", a[i]);    putchar('\n');}int main(void){    int a[10] = {0};    printf("in main, sizeof a = %u\n", sizeof(a));    printf("---------------------\n");    test(a);    printf("=====================\n");    rand_a(a, sizeof(a) / sizeof(a[0]));    print_a(a, sizeof(a) / sizeof(a[0]));    return 0;}运行结果:in main, sizeof a = 40---------------------in test, sizeof a = 4=====================83 86 77 15 93 35 86 92 49 21

03c99_define.c

#include <stdio.h>int main(void){    // C99    int a[] = { [0] = 32, [3] = 45, [4] = 16 };    int i = 0;    for (i = 0; i < sizeof(a) / sizeof(a[0]); i++)        printf("a[%d] = %d\n", i, a[i]);    return 0;}运行结果:a[0] = 32a[1] = 0a[2] = 0a[3] = 45a[4] = 16

04array_operation.c

#include <stdio.h>void rand_a(int a[], int len){    int i = 0;    for (i = 0; i < len; i++)        a[i] = rand() % 100;}void print_a(int a[], int len){    int i = 0;    for (i = 0; i < len; i++)        printf("%d ", a[i]);    putchar('\n');}int max(int a[], int len){    int i = 0, max = a[0];    for (i = 0; i < len; i++)    {        if (a[i] > max)            max = a[i];    }    return max;}int min(int a[], int len){    int i = 0, min = a[0];    for (i = 0; i < len; i++)    {        if (a[i] < min)            min = a[i];    }    return min;}void reverse(int a[], int len){    int i = 0;    for (i = 0; i < len / 2; i++)    {        a[i] ^= a[len-i-1];        a[len-i-1] ^= a[i];        a[i] ^= a[len-i-1];    }}void bubble_sort(int a[], int len){    int i = 0, j = 0;    for (i = 0; i < len - 1; i++)    {        for (j = 0; j < len - i - 1; j++)        {            if (a[j] > a[j+1])            {                a[j] ^= a[j+1];                a[j+1] ^= a[j];                a[j] ^= a[j+1];            }        }    }}int main(void){    int a[10] = {0};    rand_a(a, 10);    print_a(a, 10);    printf("--------------------\n");    printf("max = %d\n", max(a, 10));    printf("min = %d\n", min(a, 10));    printf("--------------------\n");    printf("reverse:\n");    reverse(a, 10);    print_a(a, 10);    printf("--------------------\n");    printf("sort:\n");    bubble_sort(a, 10);    print_a(a, 10);    return 0;}运行结果:83 86 77 15 93 35 86 92 49 21--------------------max = 93min = 15--------------------reverse:21 49 92 86 35 93 15 77 86 83--------------------sort:15 21 35 49 77 83 86 86 92 93

05char_array.c

#include <stdio.h>#include <string.h>int main(void){    // char str[] = {'c', 'h', 'i', 'n', 'a', ' ', 'u', 'n', 'i', 'x', '\0' };    char str[] = "china unix";    // 在内存中, 默认字符串以 '\0' 结束. 即 '\0' 是字符串结束的标志.    // '\0' 结尾字符 NUL字符 空字符 ascii编码为 0    // '0'  0字符                   ascii编码为 48    // sizeof 是一个运算符, 它在编译期求值(数组的元素个数).    printf("sizeof str = %u\n", sizeof(str));    // strlen 是库函数, 它在运行期求值(不包含'\0'的字符个数).    printf("length of str = %u\n", strlen(str));    printf("------------------------\n");    printf("sizeof \"china unix\" = %u\n", sizeof "china unix");    // 要用 \ 来显示双引号    printf("length of \"china unix\" = %u\n", strlen("china unix"));    printf("========================\n");    // s 空间放不下 '\0', 错误.    char s[10] = "china unix";    // s1 空间足够放下字符串. 没有赋 '\0'.    // 给了数组初始化式后, 未初始化的部分自动赋0(就是'\0')    // 如下初始化式是正确的.    char s1[10] = { 'C', 'H', 'I', 'N', 'A' };    printf("s[10] = %s\n", s); // 会把s1也给打印出来, 因为s1在栈中是放在了s之后的, 且s1有尾零    return 0;}运行结果:sizeof str = 11length of str = 10------------------------sizeof "china unix" = 11length of "china unix" = 10========================s[10] = china unixCHINA

06out_of_range.c

#include <stdio.h>int main(void){    int b = 25;    int a[5] = { 1, 2, 3, 4, 10 };    int i = 0;    // 屏蔽与不屏蔽的运行结果不一样    printf("&b = %p\n", &b);    printf("a  = %p\n", a);    printf("&i = %p\n", &i);    // i == 5 时越界了.    for (i = 0; i < 6; i++)        printf("a[%d] = %d\n", i, a[i]);    a[5] = 36;  // 越界    // 这是一种巧合.    printf("b = %d\n", b);    return 0;}运行结果(屏蔽掉3句打印地址值的printf):a[0] = 1a[1] = 2a[2] = 3a[3] = 4a[4] = 10a[5] = 5    -->  随机值b = 25运行结果(不屏蔽3句打印地址值的printf):&b = 0xbfe0aca8a  = 0xbfe0ac94&i = 0xbfe0acaca[0] = 1a[1] = 2a[2] = 3a[3] = 4a[4] = 10a[5] = 25    -->  b的值b = 36       -->  b被修改了

07infinite_loop.c

#include <stdio.h>int main(void){    int a[5] = { 12, 34, 56, 78, 90 };    int i = 0;    printf("a  = %p\n", a);    printf("&i = %p\n", &i);    // 越界访问导致无限循环(这是一种巧合).    for (i = 0; i < 5; i++)    {        printf("%d\n", a[i]);        a[5] = 2; // 越界, 相当于 i = 2;        sleep(1);    }    return 0;}运行结果:a  = 0xbf9eeef8&i = 0xbf9eef0c127878787878...

08puts.c

#include <stdio.h>int main(void){    char s1[10] = "helloworld";   // 没有尾零    char s2[] = "HELLO";          // 有尾零    // 输出到 '\0' 停止, 自动加换行. 等价于 printf("%s\n", s1);    puts(s1);    printf("--------------\n");    puts(s2);    return 0;}运行结果:helloworldHELLO--------------HELLO

09gets.c

#include <stdio.h>int main(void){    char s[1024] = {0};    printf("pls input a string: ");    gets(s);    // scanf("%s", s);    printf("-----------\n");    printf("you inputed: ");    puts(s);    // printf("%s\n", s);    return 0;}

10my_atoi.c

#include <stdio.h>int judge_format(char s[]){    int i = 0;    while (s[i] != '\0')    {        if (!('0' <= s[i] && s[i] <= '9'))            break;        i++;    }    if (s[i] == '\0')   // 表示已到尽头        return 1;    else        return 0;}unsigned int my_atoi(char s[]){    int i = 0;    unsigned int n = 0;    while (s[i] != '\0')    {        n *= 10;        n += s[i++] - '0';    }    return n;}int main(void){    char s[128] = {0};    unsigned int a = 0;retry:    printf("pls input a string: ");    gets(s);    if (judge_format(s))    {        a = my_atoi(s);        printf("a = %u\n", a);    }    else    {        printf("pls input a integer.\n");        goto retry;    }    return 0;}

exercise1.c

#include <stdio.h>#include <string.h>int insert_char(char s[], int len, int index, char ch)// 指定下标插入{    int i = 0, s_len = strlen(s);    if((s_len + 1) >= len) // 包括将要插入的字符在内, 是否大于等于len, 等于的话, 尾零就放不下了    {        printf("input string too long!\n");        return -1;    }    if(index < 0 || index > s_len)    {        printf("input wrong index!\n");        return -1;    }    i = s_len;    while(i >= index)    {        s[i+1] = s[i]; // 往后挪一位        i--;    }    s[index] = ch;    return 0;}int main(void){    char s[128] = {0};    char ch = '0';    int index = 0, ret = 0;    printf("input a string: ");    gets(s);retry:    printf("input a index to insert your char: ");    ret = scanf("%d", &index);    // 清空输入缓冲区.    while(getchar() != '\n')        ;    if(ret == 0)    {        printf("input wrong format, pls input again.\n");        goto retry;    }    printf("input the character you wanna insert: ");    ch = getchar();    if(0 == insert_char(s, sizeof(s)/sizeof(s[0]), index, ch))    {        printf("insert succeed!\n");        puts(s);    }    else    {        printf("insert failed!\n");    }    return 0;}往字符串中插入字符运行结果:input a string: abcdefghjiklmninput a index to insert your char: 5input the character you wanna insert: Winsert succeed!abcdeWfghjiklmn

exercise2.c

#include <stdio.h>int my_strlen(const char src[]) // 获取字符串长度{    int len = 0;    while(src[len++] != '\0')        ;    return len - 1;}void my_strcpy(char dest[], const char src[]) // 拷贝字符串{    int i = 0;    while(src[i] != '\0')    {        dest[i] = src[i];        i++;    }    dest[i] = '\0'; // 最后别忘了再赋一个尾零}void my_strcat(char dest[], const char src[]) // 在一个字符串的结尾追加另一个字符串{    int d_len = my_strlen(dest);    my_strcpy(dest + d_len, src); // dest 先偏移 d_len 个单位, 再传给 my_strcpy}int my_strcmp(const char s1[], const char s2[]) // 比较两个字符串{    int i = 0;    while((s1[i] != '\0') && (s2[i] != '\0'))    {        if(s1[i] != s2[i])            break;        i++;    }    return (s1[i] - s2[i]);}char *my_strchr(char *src, int ch) // 在src中查找第一次c出现的位置, 并返回该位置的指针{    int i = 0;    while(src[i] != '\0')    {        if(src[i] == ch)            return (src+i);        i++;    }    return NULL;}char *my_strstr(char parent[], char child[]) // 在parent中查找第一次child出现的位置, 并返回该位置的指针{    int i = 0, j = 0, start_pos = 0;    for(i = 0; parent[i] != '\0'; i++)    {        if(parent[i] == child[0]) // 和 child 的首字符相等了再进来继续判断        {            start_pos = i;            for(j = 1; child[j] != '\0'; j++) // j 从 1 开始            {                if(parent[++start_pos] != child[j])                    break;            }            if(child[j] == '\0')                return (parent+i); // i 保存的就是起始位置        }    }    return NULL;}int main(void){    char dest[1024] = {0}, src[1024] = {0};    int ret = 0;    char *str = NULL;    printf("please input a string: ");    gets(src);    printf("len = %d\n", my_strlen(src));    printf("------------------\n");    printf("src  = %s\n", src);    my_strcpy(dest, src);    printf("dest = %s\n", dest);    printf("------------------\n");    my_strcat(dest, src);    printf("dest = %s\n", dest);    printf("------------------\n");    ret = my_strcmp(dest, src);    if(ret == 0)        printf("dest == src\n");    if(ret > 0)        printf("dest > src\n");    if(ret < 0)        printf("dest < src\n");    printf("------------------\n");    str = my_strchr(dest, '5');    printf("str = %s\n", str);    printf("------------------\n");    str = my_strstr(dest, "abcd");    printf("str = %s\n", str);    return 0;}实现 my_strlen, my_strcpy, my_strcat, my_strcmp, my_strchr, my_strstr运行结果:please input a string: 0123456789abcdelen = 15------------------src  = 0123456789abcdedest = 0123456789abcde------------------dest = 0123456789abcde0123456789abcde------------------dest > src------------------str = 56789abcde0123456789abcde------------------str = abcde0123456789abcde

exercise3.c

#include <stdio.h>#include <string.h>void reverse(char s[], int len){    int i;    for (i = 0; i < len/2; i++)    {        s[i] ^= s[len-i-1];        s[len-i-1] ^= s[i];        s[i] ^= s[len-i-1];    }}void add(char s1[], char s2[], char sum[]){    int len1 = strlen(s1);    int len2 = strlen(s2);    int len_max = len1 > len2 ? len1 : len2;    // 为了更方便的运用数组操作, 需要倒置一下字符串    reverse(s1, len1);    reverse(s2, len2);    int i = 0, digit = 0, carry = 0;    for (i = 0, digit = 0; i < len_max; i++, digit = 0)    {        if (s1[i] != '\0')            digit += s1[i] - '0';        if (s2[i] != '\0')            digit += s2[i] - '0';        digit += sum[i]; // 加上前一次可能的进位.        sum[i] = digit % 10;        carry = digit / 10;        if (carry != 0)            sum[i + 1] = carry;        sum[i] += '0'; // 转成字符    }    if (sum[i] != 0)        sum[i] += '0';    reverse(sum, strlen(sum)); // 最后再逆转回来    reverse(s1, len1);    reverse(s2, len2);}int main(void){    char s1[128] = {0}, s2[128] = {0}, sum[128] = {0};    printf("input s1: ");    gets(s1);    printf("input s2: ");    gets(s2);    add(s1, s2, sum);    printf("%s + %s = %s\n", s1, s2, sum);    return 0;}字符串加法, 如: "123" + "999" = "1122"实现大数据的相加.运行结果:input s1: 658495129756984566587566458input s2: 498956238486532169463235544658495129756984566587566458 + 498956238486532169463235544 = 1157451368243516736050802002
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