leetcode--------------Length of Last Word

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Given a string s consists of upper/lower-case alphabets and empty space characters ' ', return the length of last word in the string.

If the last word does not exist, return 0.

Note: A word is defined as a character sequence consists of non-space characters only.

For example, 
Given s = "Hello World",
return 5.


程序代码如下:


import java.util.Scanner;


public class Length_of_LastWord {

public static void main(String[] args) {

Scanner inputString = new Scanner(System.in);
String s = inputString.nextLine();

System.out.println(lengthOfLastWord(s));
}
public static  int lengthOfLastWord(String s) {
int sLength = s.length() - 1;
int count = 0;


for(;sLength >= 0;sLength--){
if(s.charAt(sLength) != ' '){
break;
}
}

for(;sLength >= 0;sLength--){
if(s.charAt(sLength) != ' '){
count++;
}else
break;
}

return count;
}

}

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