1058. A+B in Hogwarts (20)

题目链接：http://www.patest.cn/contests/pat-a-practise/1058

题目：

If you are a fan of Harry Potter, you would know the world of magic has its own currency system -- as Hagrid explained it to Harry, "Seventeen silver Sickles to a Galleon and twenty-nine Knuts to a Sickle, it's easy enough." Your job is to write a program to compute A+B where A and B are given in the standard form of "Galleon.Sickle.Knut" (Galleon is an integer in [0, 10⁷], Sickle is an integer in [0, 17), and Knut is an integer in [0, 29)).

Input Specification:

Each input file contains one test case which occupies a line with A and B in the standard form, separated by one space.

Output Specification:

For each test case you should output the sum of A and B in one line, with the same format as the input.

Sample Input:

3.2.1 10.16.27

Sample Output:

14.1.28

分析：

数制转换
17个银西可等于一个加隆，而29个科纳等于一个西可

AC代码：

#include<stdio.h>using namespace std;struct Number{ int high; int mid; int low;};int main(){ freopen("F://Temp/input.txt", "r", stdin); Number num1, num2,num_sum; scanf("%d.%d.%d", &num1.high, &num1.mid, &num1.low); scanf("%d.%d.%d", &num2.high, &num2.mid, &num2.low); num_sum.low = num1.low + num2.low; num_sum.mid = num1.mid + num2.mid; num_sum.high = num1.high + num2.high; num_sum.mid += num_sum.low / 29; num_sum.high += num_sum.mid / 17; num_sum.mid = num_sum.mid % 17; num_sum.low = num_sum.low % 29; printf("%d.%d.%d\n", num_sum.high, num_sum.mid, num_sum.low); return 0;}

截图：

——Apie陈小旭