LeetCode || Reverse Integer
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class Solution {public: int reverse(int x) { int positive = 1; if(x < 0) { positive = -1; x *=(-1); } unsigned int reverseX = 0; while(x !=0) { if(reverseX > INT_MAX/10)//一定要判断是否溢出。 { reverseX = 0; break; } reverseX *= 10; reverseX += x%10; x = x/10; } return reverseX*positive; }};
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