获取最优服务的QOS值

来源：互联网发布：gunicorn windows 编辑：程序博客网时间：2024/06/05 20:44
#include<cstdio>#include<iostream>#include<cstdlib>#include<math.h>using namespace std;int main(){int SU[5][10][3]={{{7,8,7},{6,7,8},{6,7,5},{6,7,6},{6,7,9},{7,9,8},{8,8,7},{9,6,8},{8,6,9},{10,6,8}},{{8,8,6},{9,6,7},{7,6,6},{8,7,5},{6,6,7},{8,7,9},{9,9,6},{7,6,9},{6,7,8},{8,9,8}},{{7,7,9},{8,7,7},{6,6,7},{9,6,8},{7,7,8},{5,5,6},{4,4,6},{8,8,7},{9,8,6},{5,4,6}},{{9,7,8},{7,8,7},{9,9,8},{8,7,7},{8,9,7},{8,8,6},{7,6,7},{8,7,6},{8,5,8},{7,7,7}},{{8,6,7},{6,7,8},{8,8,7},{7,7,8},{9,8,6},{6,7,8},{7,7,8},{8,8,7},{6,8,7},{9,9,7}}};//cout<<SU[1][2]<<endl;float b[3]={0.5,0.3,0.2};int N = 5,m = 0,max = 0;float SUM[10]={0},sim[5][10]={0},AVE[10][3]={0},c[5][10][3]={0};int a[5]={0};float QOS[10]={0.0},su[5][10]={0.0},ave[10]={0.0};int i,j,k;//cout<<b[1]<<endl;for(i = 0;i < 5;i++){for(j=0;j<10;j++){for(k=0;k<3;k++){su[i][j] += SU[i][j][k]*b[k];//cout<<b[1]<<endl;}//cout<<SU[i][j][k]*b[k]<<endl;//printf("输出用户%d对于服务%d的综合评价值: %.4f\n",i+1,j+1,su[i][j]);}}for(j=0;j<10;j++){float M = 0.0000;for(i=0;i<5;i++){//int M = 0;M += su[i][j];}if(i==5){ave[j] = M/5;printf("第%d个服务的平均值： %.4f\n",j,ave[j]);}}for(j=0;j<10;j++){for(i=0;i<5;i++){if (fabs(su[i][j]-ave[j])>=0.3)a[i]++;}}for(i=0;i<5;i++){if (a[i]>=4){for(j=0;j<10;j++){for(k=0;k<3;k++){SU[i][j][k]=0; }}N--;           //相当于将此用户从三维数组中删除}}printf("最终剩下%d个可信用户\n", N);//接下来根据剩余的可信用户，求各服务的预估向量值for(i=0;i<5;i++){for(j=0;j<10;j++){for(k=0;k<3;k++){c[i][j][k]+=SU[i][j][k];}}AVE[j][k] = c[i][j][k]/N;}//进行相似度计算for(i=0;i<5;i++){for(j=0;j<10;j++){sim[i][j] = (AVE[j][0]*SU[i][j][0]+AVE[j][1]*SU[i][j][1]+AVE[j][2]*SU[i][j][2])/(float) sqrt((float)(AVE[j][0]*AVE[j][0]+AVE[j][1]*AVE[j][1]+AVE[j][2]*AVE[j][2])*(SU[i][j][0]*SU[i][j][0]+SU[i][j][1]*SU[i][j][1]+SU[i][j][2]*SU[i][j][2]));}}//各服务的相似度之和for(j=0;j<10;j++){for(i=0;i<5;i++){SUM[j] += sim[i][j];}}//计算各服务的QoS值for(j=0;j<10;j++){for(i=0;i<5;i++){//for(k=0;k<3;k++)//{QOS[j] += sim[i][j]*(su[i][j]/SUM[j]);//}}//printf("输出各服务的QOS值: \n");//printf (" %d ",QOS[j]);if(QOS[j]>=max){max=QOS[j];m=j;}}printf("目标用户应该选择第%d个服务\n",m);system("pause");return 0;}
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