zoj1005

来源:互联网 发布:mac 终端退出 bash 编辑:程序博客网 时间:2024/05/16 17:16

这道题其实只需要模拟就好了

#include <iostream>using namespace std;int main(){    int juga,jugb,n,t;    while(cin>>juga>>jugb>>n)    {        if(jugb == n)        {            cout<<"fill B"<<endl;            cout<<"success"<<endl;            continue;        }        if(juga == n)        {            cout<<"fill A"<<endl;            cout<<"pour A B"<<endl;            cout<<"success"<<endl;            continue;        }        t = 0;        while(t != n)        {            cout<<"fill A"<<endl<<"pour A B"<<endl;            t += juga;            if(t > jugb)            {                t -= jugb;                cout<<"empty B"<<endl<<"pour A B"<<endl;            }        }        cout<<"success"<<endl;    }}
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