02-线性结构2 Reversing Linked List

#include <stdio.h>#define MAX_SIZE 100001typedef struct node{int address;int data;int next_address;struct node * next;} Node; Node * ListReverse(Node * L, int k);void PrintList(Node * L);int main(int argc, char const *argv[]){int first_address;//首地址int temp_address;//临时变量，输入的时候用int n = 0;//节点数 N    int k = 0;//反转子链表的长度K    int num = 0;//链表建好之后的链表节点数int Data[MAX_SIZE];//存data值 节点位置作为索引值int Next_address[MAX_SIZE];//存next_address值 节点位置为索引scanf("%d %d %d", &first_address, &n, &k);Node a[n+1];a[0].next_address = first_address;for(; i < n; i++){scanf("%d", &temp_address);scanf("%d %d", &Data[temp_address], &Next_address[temp_address]);}i = 1;while(1){if(a[i-1].next_address == -1){a[i-1].next = NULL;num = i - 1;break;}a[i].address = a[i-1].next_address;a[i].data = Data[a[i].address];a[i].next_address = Next_address[a[i].address];a[i-1].next = a + i;i++;}Node *p = a;Node *rp = NULL;//rp:反转链表函数的返回值if(k <= num){for (int i = 0; i < (num/k); i++){rp = ListReverse(p, k);p->next = rp;p->next_address = rp->address;for (int j = 0; j < k; j++){p = p->next;//使p指向下一段需要反转的子链表的头结点（第一个节点的前一个节点）}}}PrintList(a);return 0;}Node * ListReverse(Node * L, int k){int count = 1;Node * current, * pnext, * prev;current = L->next;//定义当前结点 current，初始值为首元结点，current = L->next;pnext = current->next;//定义当前结点的后继结点 pnext， pnext = current->next; while(count < k){prev = pnext->next;//定义新节点 prev，它是 pnext的后继结点，prev = pnext->next;pnext->next = current;//把pnext的后继指向current, pnext->next = current;pnext->next_address = current->address;current = pnext;//此时，pnext 实际上已经到了 current 前一位成为新的current，所以这个时候 current 结点实际上成为新的 pnext，current = pnext;pnext = prev;//而新的 pnext 就是 prev，pnext = prev;count++;}L->next->next = pnext;//使反转后的最后一个节点指向下一段子链表的第一个节点if(pnext != NULL){L->next->next_address = pnext->address;}else{L->next->next_address = -1;}return current;}void PrintList(Node * L){Node * P = L;while(P->next != NULL){P = P->next;if(P->next_address == -1)printf("%.5d %d %d\n", P->address, P->data, P->next_address);//格式输出，%.5意味着如果一个整数不足5位，输出时前面补0 如：22，输出：00022elseprintf("%.5d %d %.5d\n", P->address, P->data, P->next_address);}}