HDU 5480：Conturbatio 前缀和

Conturbatio

Time Limit: 6000/3000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others)
Total Submission(s): 232    Accepted Submission(s): 108

Problem Description

There are many rook on a chessboard, a rook can attack the row and column it belongs, including its own place.

There are also many queries, each query gives a rectangle on the chess board, and asks whether every grid in the rectangle will be attacked by any rook?

 

Input

The first line of the input is a integer T, meaning that there are T test cases.

Every test cases begin with four integers n,m,K,Q.
K is the number of Rook, Q is the number of queries.

Then K lines follow, each contain two integers x,y describing the coordinate of Rook.

Then Q lines follow, each contain four integers x1,y1,x2,y2 describing the left-down and right-up coordinates of query.

1≤n,m,K,Q≤100,000.

1≤x≤n,1≤y≤m.

1≤x1≤x2≤n,1≤y1≤y2≤m.

 

Output

For every query output "Yes" or "No" as mentioned above.

 

Sample Input

22 2 1 21 11 1 1 22 1 2 22 2 2 11 11 22 1 2 2

 

Sample Output

YesNoYes
Hint
Huge input, scanf recommended.

题意是一个棋盘上有很多车，车可以攻击他所属的一行或一列，包括它自己所在的位置。现在有很多询问，每次询问给定一个棋盘内部的矩形，问矩形内部的所有格子是否都被车攻击到？

对自己的智商感到不断怀疑系列。。。判断中间有没有零，求和啊

代码：

#include <iostream>  #include <algorithm>  #include <cmath>  #include <vector>  #include <string>  #include <cstring>#include <stack>#pragma warning(disable:4996)  using namespace std;int row[100005];int column[100005];int main(){int test,i,j,flag1,flag2;int n,m,k,q,x,y,x1,x2,y1,y2;scanf("%d",&test);while(test--){scanf("%d%d%d%d",&n,&m,&k,&q);memset(row,0,sizeof(row));memset(column,0,sizeof(column));for(i=1;i<=k;i++){scanf("%d%d",&x,&y);row[x]=1;column[y]=1;}for(i=1;i<=n;i++){row[i]=row[i]+row[i-1];}for(i=1;i<=m;i++){column[i]=column[i]+column[i-1];}for(i=1;i<=q;i++){scanf("%d%d%d%d",&x1,&y1,&x2,&y2);if(x2-x1+1==row[x2]-row[x1-1]||y2-y1+1==column[y2]-column[y1-1]){puts("Yes");}else{puts("No");}}}return 0;}