【Violet3】【BZOJ2716】天使玩偶
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Description
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Source
在题面里放大样例…我该说Vani良心?
样例太长了不放进去了
在以前看的课件里见过这题
#include<iostream>#include<cstdio>#include<cstring>#include<cmath>#include<algorithm>#define MAXN 1000100#define lowbit(x) (x&(-x))#define MAXINT 0x7fffffffusing namespace std;int n,m,size;int c[MAXN],ans[MAXN];void in(int &x){ char ch=getchar();x=0;int flag=1; while (!(ch>='0'&&ch<='9')) flag=ch=='-'?-1:flag,ch=getchar(); while (ch>='0'&&ch<='9') x=x*10+ch-'0',ch=getchar();}void add(int x,int delta){ for (int i=x;i<=size;i+=lowbit(i)) c[i]=max(c[i],delta);}int query(int x){ int ret=0; for (int i=x;i;i-=lowbit(i)) ret=max(ret,c[i]); return ret;}void init(int x){ for (int i=x;i<=size;i+=lowbit(i)) c[i]=0;}struct Query{ int opt,x,y,id; bool operator <(const Query& a)const { return x==a.x?id<a.id:x<a.x; }}q[MAXN],newq[MAXN];void solve(int l,int r){ int mid=(l+r)>>1,tp1=l,tp2=mid+1; if (l==r) return; for (int i=l;i<=r;i++) if (q[i].id<=mid) newq[tp1++]=q[i]; else newq[tp2++]=q[i]; memcpy(q+l,newq+l,sizeof(Query)*(r-l+1)); solve(l,mid); int i=mid+1,j=l; for (i=mid+1;i<=r;i++) if (q[i].opt==2) { for (;j<=mid&&q[j].x<=q[i].x;j++) if (q[j].opt==1) add(q[j].y,q[j].x+q[j].y); int temp=query(q[i].y); if (temp) ans[q[i].id]=min(ans[q[i].id],q[i].x+q[i].y-temp); } for (i=l;i<j;i++) if (q[i].opt==1) init(q[i].y); solve(mid+1,r); tp1=l,tp2=mid+1; for (i=l;i<=r;i++) if ((q[tp1]<q[tp2]||tp2>r)&&tp1<=mid) newq[i]=q[tp1++]; else newq[i]=q[tp2++]; memcpy(q+l,newq+l,sizeof(Query)*(r-l+1)); }int main(){ in(n);in(m); for (int i=1;i<=n;i++) scanf("%d%d",&q[i].x,&q[i].y),q[i].id=i,q[i].opt=1,q[i].x++,q[i].y++,size=max(size,max(q[i].x,q[i].y)); for (int i=n+1;i<=n+m;i++) scanf("%d%d%d",&q[i].opt,&q[i].x,&q[i].y),q[i].id=i,q[i].x++,q[i].y++,size=max(size,max(q[i].x,q[i].y)); size++; for (int i=1;i<=n+m;i++) ans[i]=MAXINT; sort(q+1,q+n+m+1);solve(1,n+m); for (int i=1;i<=n+m;i++) q[i].x=size-q[i].x; sort(q+1,q+n+m+1);solve(1,n+m); for (int i=1;i<=n+m;i++) q[i].y=size-q[i].y; sort(q+1,q+n+m+1);solve(1,n+m); for (int i=1;i<=n+m;i++) q[i].x=size-q[i].x; sort(q+1,q+n+m+1);solve(1,n+m); for (int i=1;i<=n+m;i++) if (ans[i]!=MAXINT) printf("%d\n",ans[i]);}
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