Leetcode Word Search
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Leetcode Word Search 相关代码,本代码使用dfs(广度优先搜索)算法,以下给出代码示例,以及相关测试:
#include<vector>#include<iostream>#include<string>using namespace std;/* * We use the DFS algorithm complete this problem. */class Solution {public: bool exist(vector<vector<char> >& board, string word) { // Save the Row and Col to reduce the cost by invoke the vector::size() int Row = board.size(); int Col = 0; if (Row > 0) { Col = board[0].size(); } for (int i = 0; i < Row; i ++) { for (int j = 0; j < Col; j ++) { if (search(board, word, 0, i, j, Row, Col)) { return true; } } } return false; } // use recursive and dfs to solve this problem bool search(vector<vector<char> >& board, string& word, int pos, int pos_x, \ int pos_y, int Row, int Col) { if (word.length() == pos) { return true; } else { if (pos_x < 0 || pos_x >= Row || pos_y < 0 || pos_y >= Col \ || board[pos_x][pos_y] == ' ') { return false; } if (board[pos_x][pos_y] == word[pos]) { char temp = board[pos_x][pos_y]; board[pos_x][pos_y] = ' '; bool re = search(board, word, pos + 1, pos_x + 1, pos_y, Row, Col) || \ search(board, word, pos + 1, pos_x - 1, pos_y, Row, Col) || \ search(board, word, pos + 1, pos_x, pos_y + 1, Row, Col) || \ search(board, word, pos + 1, pos_x, pos_y - 1, Row, Col); if (re) { return true; } else { board[pos_x][pos_y] = temp; } } return false; } }};int main(int argc, char* argv[]) { vector<vector<char> > test; vector<char> ele1(2, 'a'); vector<char> ele2(2, 'b'); test.push_back(ele1); test.push_back(ele2); Solution so; bool re = so.exist(test, "abba"); cout<<"result: "<<re<<endl; return 0;}
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