LeetCode----Power of Two
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Power of Two
Given an integer, write a function to determine if it is a power of two.
Credits:
Special thanks to @jianchao.li.fighter for adding this problem and creating all test cases.
分析：
简单题，判断一个数是否是2的倍数。我先统计出给定数的二进制中1的个数，如果个数大于1，则为False。
相关学习链接：快速求二进制中1的个数，位运算。
代码：
class Solution(object): def isPowerOfTwo(self, n): """ :type n: int :rtype: bool """ if n <= 0: return False count = 0 while n: n &= n - 1 count += 1 if count == 1: return True else: return False
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