2015 CCPC A题 【水题】

题目链接 点我

题意：给你两个二维矩阵A和B，问你矩阵A能否通过矩阵B旋转得到。

思路：直接暴力。

AC代码：

#include <cstdio>#include <cstring>#include <cmath>#include <cstdlib>#include <algorithm>#include <map>#include <string>#include <vector>#define lson o<<1|1, l, mid#define rson o<<1, mid+1, r#define ll o<<1#define rr o<<1|1#define INF 0x3f3f3f3f#define eps 1e-8#define debug printf("1\n")#define MAXN 10000#define MAXM 100000#define LL long long#define CLE(a, b) memset(a, (b), sizeof(a))#define W(a) while(a--)#define Ri(a) scanf("%d", &a)#define Pi(a) printf("%d\n", (a))#define Rl(a) scanf("%lld", &a)#define Pl(a) printf("%lld\n", (a))using namespace std;int main(){    int t, kcase = 1;    scanf("%d", &t);    W(t)    {        int a0, b0 ,c0, d0;        int a1, b1, c1, d1;        Ri(a0); Ri(b0); Ri(c0); Ri(d0);        Ri(a1); Ri(b1); Ri(c1); Ri(d1);        bool s1 = (a0 == a1 && b0 == b1 && c0 == c1 && d0 == d1);        bool s2 = (a0 == b1 && b0 == d1 && c0 == a1 && d0 == c1);        bool s3 = (a0 == d1 && b0 == c1 && c0 == b1 && d0 == a1);        bool s4 = (a0 == c1 && b0 == a1 && c0 == d1 && d0 == b1);        if(s1 || s2 || s3 || s4)            printf("Case #%d: POSSIBLE\n", kcase++);        else            printf("Case #%d: IMPOSSIBLE\n", kcase++);    }    return 0;}