HDOJ 5500 Reorder the Books(贪心)

Reorder the Books

Time Limit: 4000/2000 MS (Java/Others)    Memory Limit: 131072/131072 K (Java/Others)
Total Submission(s): 726    Accepted Submission(s): 417

Problem Description

dxy has a collection of a series of books called "The Stories of SDOI",There aren(n≤19) books in this series.Every book has a number from 1 to n.

dxy puts these books in a book stack with the order of their numbers increasing from top to bottom. dxy takes great care of these books and no one is allowed to touch them.

One day Evensgn visited dxy's home, because dxy was dating with his girlfriend, dxy let Evensgn stay at home himself. Evensgn was curious about this series of books.So he took a look at them. He found out there was a story about "Little E&Little Q". While losing himself in the story,he disrupted the order of the books.

Knowing that dxy would be back soon,Evensgn needed to get the books ordered again.But because the books were too heavy.The only thing Evensgn could do was to take out a book from the book stack and and put it at the stack top.

Give you the order of the disordered books.Could you calculate the minimum steps Evensgn would use to reorder the books? If you could solve the problem for him,he will give you a signed book "The Stories of SDOI 9: The Story of Little E" as a gift.

 

Input

There are several testcases.

There is an positive integer T(T≤30) in the first line standing for the number of testcases.

For each testcase, there is an positive integer n in the first line standing for the number of books in this series.

Followed n positive integers separated by space standing for the order of the disordered books,theith integer stands for the ith book's number(from top to bottom).


Hint:
For the first testcase:Moving in the order of book3,book2,book1 ,(4,1,2,3)→(3,4,1,2)→(2,3,4,1)→(1,2,3,4),and this is the best way to reorder the books.
For the second testcase:It's already ordered so there is no operation needed.

 

Output

For each testcase,output one line for an integer standing for the minimum steps Evensgn would use to reorder the books.

 

Sample Input

244 1 2 351 2 3 4 5

 

Sample Output

30大意：每次可以从第一位后面选一个数放到第一位，问操作几次之后能将数变为顺序数思路：刚开始直接看了样例，理解错了题，最后一看题才知道不是那样，晕，先找最大的那个数，找到后自减然后找下一个，如果第一位就是最大的，那么共需要n步，即按顺序从后面挑选n次数。ac代码：
#include<stdio.h>#include<string.h>#include<iostream>#include<algorithm>#define MAXN 201000#define MAX(a,b) a>b?a:b#define fab(a) a>0?a:-ausing namespace std;int a[MAXN];int main(){int t,i,j,n,num;scanf("%d",&t);while(t--){scanf("%d",&n);for(i=0;i<n;i++)scanf("%d",&a[i]);int num=n;for(int k=n-1;k>=0;){if(a[k]==num)num--;k--;}printf("%d\n",num);}return 0;}