数字串转中文读法串-Java实现

来源：互联网发布：bpm软件架构编辑：程序博客网时间：2024/06/05 08:22

面试时被问到这个问题，遂查看相关博客，自己也作了相应的实现：

package num2rmb;public class Num2Rmb3 {/** * 处理0，1,2.。9的中文读法的 */private String[] hanArr = {"零" , "壹" , "贰" , "叁" , "肆" , "伍" , "陆" , "柒" , "捌" , "玖"};/** * 10进制的读法 */private String[] unitArr = {"十" , "百" , "千"};public static void main(String[] args) {Num2Rmb3 nr = new Num2Rmb3();nr.readNumString("1052433768");//nr.readNumString("5000");//System.out.println(Math.ceil(3.5));   //4.0}public void readNumString(String numstr){StringBuilder sb = new StringBuilder();int len = numstr.length();int count = 0;while (len > 0)    //依次取出最后，以4位字符为标准取子串{int i = (len - 4) >= 0 ? (len - 4) : 0;String temp = numstr.substring(i, len);System.out.println(temp);String res = processTemp(temp, count);  // 对这四个字符进行处理sb.insert(0, res);              //往前将求得的字符串插入sb中len -= 4;count++;  // 记录这个子串中能组成多少个 4个字符的串}System.out.println(sb);}public String processTemp(String temp, int count){String res = "";int len1 = temp.length();// 0042// 200for (int i = 0; i < len1; i++){//将每个字符转成数字int num = temp.charAt(i) - 48;if (num == 0)  //如果是0{if (i == (len1 - 1))  //到了子串的最后一个字符{continue;}//如果下一个是数字字符不是0if (temp.charAt(i + 1) != '0'){res += hanArr[num];}else {continue;}}else if( i == (len1 - 1) ) {  //不是0,最后一个字符res += hanArr[num];}else  //{res += hanArr[num] + unitArr[len1 - i - 2];}}if (count == 1){res += "万";}else if (count == 2){res += "亿";}return res;}}

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