java佩恩沃星球打怪掉血实现

来源：互联网发布：保安巡更软件编辑：程序博客网时间：2024/04/29 00:35
public int[] daguai(int arr[]) {System.out.println("Do You Want To Play Now(1.yes-2.no)");int a = new Scanner(System.in).nextInt();int pblood = arr[0];int pattack = arr[1];int pdefase = arr[2];int mblood = arr[3];int mattack = arr[4];int mdefase = arr[5];if (a == 1) {System.out.println("玩家的生命值" + pblood + "玩家的攻击力" + pattack+ "玩家的防御力" + pdefase);System.out.println("怪物的生命值" + mblood + "怪物的攻击力" + mattack+ "怪物的防御力" + mdefase);System.out.println("Monster Is Right|attacking nums?(times)");while (mblood > 0 || pblood > 0) {System.out.println("请输入攻击次数");int b = new Scanner(System.in).nextInt();int rand = new Random().nextInt();for (int i = 0; i < 2 * b; i++) {// 这是玩家打怪物if (i % 2 != 1) {// 随机出来玩家的伤害System.out.println("*************");try {Thread.sleep(40);} catch (InterruptedException e) {// TODO Auto-generated catch blocke.printStackTrace();}int randp = new Random().nextInt(2) + 5;// System.out.println(randp+"随机数");pblood = pblood - randp * (1 - pdefase / 100);System.out.println("--玩家在流血" + pblood);if (pblood < 0) {System.out.println("--玩家死了" + pblood);break;}} else if (i % 2 == 1) {// 这是玩家被怪物打try {Thread.sleep(40);} catch (InterruptedException e) {// TODO Auto-generated catch blocke.printStackTrace();}int randm = new Random().nextInt(2) + 5;mblood = mblood - randm * (1 - mdefase / 100);// System.out.println(randm+"随机数");System.out.println("怪物正在流血" + mblood);if (mblood < 0) {System.out.println("--怪物死了" + mblood);break;}}}int resb[] = { pblood, pattack, pdefase, mblood, mattack,mdefase };for (int i = 0; i < resb.length; i++) {System.out.print("%" + resb[i]);}// System.out.println("()"+pblood+"**"+pattack+"**"+pdefase);// System.out.println(mblood+"**"+mattack+"**"+mdefase);return resb;}}return null;}
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