CodeForces 435C Cardiogram

单纯的模拟

#include <cstdio>#include <cstring>char mat[2005][1005];int main(){    int n, t;    int now_r = 1002, now_c = 0;    int up = 1002, down = 1002;    scanf("%d", &n);    memset(mat, ' ', sizeof(mat));    for(int i = 0; i < n; i++)    {        scanf("%d", &t);        for(int j = 0; j < t; j++)        {            if(i & 1) mat[now_r][now_c] = '\\', now_r++;            else mat[now_r][now_c] = '/', now_r--;            now_c++;        }        if(i & 1) now_r--;        else now_r++;        if(up > now_r) up = now_r;        if(down < now_r) down = now_r;    }    for(int i = 0; i < 2005; i++)        mat[i][now_c] = '\0';    for(int i = up; i <= down; i++)        printf("%s\n", mat[i]);    return 0;}